scala - 你如何使用 scalamock 来模拟带有构造函数参数的类

Question

我知道如何模拟一个没有构造函数参数的类

例如，myMock = mock[MockClass]

但是，如果类有构造函数参数怎么办？

更具体地说，我正在尝试模拟 finatra 类:ResponseBuilder

https://github.com/ImLiar/finatra/blob/master/src/main/scala/com/twitter/finatra/ResponseBuilder.scala

Answer 1

我在 github 上找不到测试类，但是这个问题的答案取决于你想要实现的目标。你不会使用 specs2 模拟一个类和 mockito您可以监视它以确定是否发生了某些事情，这是您可能想要实现的目标的示例。

class Responsebuilder(param1: Int, param2: int) {
    def doSomething() { doSomethingElse() }
    def doSomethingElse() { ...
}

class ResponseBuilderSpec extends Specification with Mockito {
    "response builder" should {
        "respond" in {
            val testClass = spy(new ResponseBuilder(1, 3))
            testClass.doSomething()

            there was one(testClass).doSomethingElse()
        }
    }
}

人们通常会将特征模拟为依赖项，然后在定义它们的行为后将它们注入(inject)到测试类中

trait ResponseBuilderConfig { def configurationValue: String }

class Responsebuilder(val config: ResponseBuilderConfig, param2: int) {
    def doSomething() { doSomethingElse(config.configurationValue) }
    def doSomethingElse(param: String) { ...
}

class ResponseBuilderSpec extends Specification with Mockito {
    "response builder" should {
        "respond" in {
            val mockConfig = mock[ResponseBuilderConfig]
            mockConfig.configurationValue returns "Test"
            val testClass = spy(new ResponseBuilder(mockConfig, 3))
            testClass.doSomething()

            there was one(testClass).doSomethingElse("Test")
        }
    }
}