python - 如何在 PYTHON 中的列表字典中迭代值

Question

我有一个复杂的方法需要正常工作，但我似乎无法弄清楚为什么它不能正常工作。

我有一个字典如下:

{'view': ['premium_subscribers', 'premium_content'], 'delete': ['admins', 'normal_content', 'premium_content']}

我需要知道如何逐个迭代每个特定的键值，它们是数组。例如:

key = delete

for loop (that iterates 1 by 1 through key "delete's" values
     
     takes "admins" value and does some processing

     in the next iteration takes normal_content and does same processing

     and so on ......
 
     its basically checking for a match to be found.

如果您对我的方法感兴趣，可以在下面找到。它有 3 个字典，正在比较它们的键值以完成访问权限。

如果 for 循环正确遍历该键的每个值，它将按预期开始工作。

def accessPermission(operation, user, object):

domains = dict()
types = dict()
access = dict()

    access = json.load(open("access.txt"))
    domains = json.load(open("domains.txt"))
    types = json.load(open("types.txt"))

    print(types)
    print(access)
    print(domains)

    if operation in access.keys():
        firstkeyvalue = access.get(operation)[0]
        if firstkeyvalue in domains.keys():
            if user in domains.get(firstkeyvalue):
                for access.get(operation)[0] in access:
                    if object in types.values():
                        print("Success")
                else:
                    print("Error: access denied")
            else:
                print("Error: access denied")
        else:
            print("Error: access denied")
    else:
        print("Error: access denied")

Answer 1

似乎您只需要像这样遍历元素:

dict = {'view': ['premium_subscribers', 'premium_content'], 'delete': ['admins', 'normal_content', 'premium_content']}

key = 'delete' #set somewhere
for v in dict[key]:
  print(v)
  #do what you need with that

输出:

admins
normal_content
premium_content