python - 异步函数不异步工作

Question

我有一个问题。

我写了一段模仿http请求的简单代码:

from asyncio import sleep, run


async def get():
    print("Started get()")
    await sleep(3)
    print("Finished get()")


async def async_main():
    await get()
    await get()
    await get()


if __name__ == "__main__":
    run(async_main())

我预计结果应该是这样的:

Started get()
Started get()
Started get()
(No output, just wait 3 seconds)
Finished get()
Finished get()
Finished get()

但结果是:

Started get()
(No output, just wait 3 seconds)
Finished get()
Started get()
(No output, just wait 3 seconds)
Finished get()
Started get()
(No output, just wait 3 seconds)
Finished get()

为什么会这样？

Answer 1

像下面这样异步运行任务

async def async_main():
    await asyncio.gather(get(), get(), get())

if __name__ == "__main__":
    # run(async_main()) or
    asyncio.run(async_main())