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snowflake-cloud-data-platform - 只是想检查这两个查询是否给出相同的结果或不同的结果

转载 作者:行者123 更新时间:2023-12-05 03:28:54 26 4
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查询 1:

   SELECT id,COUNT(X.C_NO) as count
FROM table X
WHERE X.date = '2022-02-02'
and P_NO is not null
group by id;

查询 2:

SELECT   id,
sum(CASE WHEN C_NO IS NOT NULL and P_NO is not null THEN 1 ELSE 0 END) as count
FROM table X
WHERE B.date = '2022-02-02'
group by id;

只是想知道这两个查询会产生相同的结果还是不同的结果

最佳答案

这些查询并不等价,它们会产生不同的结果。示例:

CREATE TABLE tab
AS
SELECT 1 AS id, NULL AS P_NO, '2022-02-02'::DATE AS date, 10 AS c_no


SELECT id,COUNT(X.C_NO) as count
FROM tab X
WHERE X.date = '2022-02-02'
and P_NO is not null
group by id;

SELECT id,
sum(CASE WHEN C_NO IS NOT NULL and P_NO is not null THEN 1 ELSE 0 END) as count
FROM tab X
WHERE X.date = '2022-02-02'
group by id;

db<>fiddle demo

输出:

enter image description here

Key子句是在GROUP BY之前执行的WHERE子句。有些行甚至在有机会被分组之前就被过滤掉了。


旁注:

第二个查询是条件聚合的示例,可以使用 COUNT_IF 聚合函数进一步简化:

SELECT id,
COUNF_IF(C_NO IS NOT NULL and P_NO is not null) as count
FROM tab X
WHERE X.date = '2022-02-02'
group by id;

关于snowflake-cloud-data-platform - 只是想检查这两个查询是否给出相同的结果或不同的结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/71148173/

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