python - 在 3D numpy 数组中填充对角线

Question

给定 3D arr，我想填充所有等于 1 的 dioganal 元素。

np.random.seed(0)
arr=np.random.rand(3,4,4)

预期产出

1,0.71519,0.60276,0.54488
0.42365,1,0.43759,0.89177
0.96366,0.38344,1,0.52889
0.56804,0.92560,0.07104,1



1,0.83262,0.77816,0.87001
0.97862,1,0.46148,0.78053
0.11827,0.63992,1,0.94467
0.52185,0.41466,0.26456,1



1,0.56843,0.01879,0.61764
0.61210,1,0.94375,0.68182
0.35951,0.43703,1,0.06023
0.66677,0.67064,0.21038,1

如下分配fill_diagonal

arr=np.fill_diagonal(arr, 1)

返回一个错误

ValueError: All dimensions of input must be of equal length

我可以知道如何正确填充 3d 数组的对角线等于 1

到目前为止正在尝试什么

arr[:,:,0] = np.diag((1,1))

ValueError: could not broadcast input array from shape (2,2) intoshape (3,4)

应避免什么

使用 for-loop 和 fill_diagonal

Answer 1

试试这个:

r = np.arange(4)
arr[:, r, r] = 1

例子:

arr = np.arange(3*4*4).reshape(3,4,4)
r = np.arange(4)
arr[:, r, r] = 1

输出:

array([[[ 1,  1,  2,  3],
        [ 4,  1,  6,  7],
        [ 8,  9,  1, 11],
        [12, 13, 14,  1]],

       [[ 1, 17, 18, 19],
        [20,  1, 22, 23],
        [24, 25,  1, 27],
        [28, 29, 30,  1]],

       [[ 1, 33, 34, 35],
        [36,  1, 38, 39],
        [40, 41,  1, 43],
        [44, 45, 46,  1]]])