bash - SED 删除字符串前的所有内容

Question

我有一个普通邮件，我需要在 过去 24 小时的客户端事件摘要之前删除所有内容
我认为它最适合 sed。

我在互联网上搜索过，但那里只有一个分隔符或类似的东西。

你有什么想法吗？

部分邮件:

...(Personal Part of the Email)...
...
The following clients have no associated schedule
NodeDomainContact
-KABA-FILESYSTEM-
-USTICA-FILESYSTEM-

Summary of client activity for the last 24 hours
DomainNodenamePlatformTypeActivityData amountElapse timeAffectedFailedMedia     wait
-FILESYSTEM-ABSYNTHE-Linux x86-64-XFS-
BACKUP-
337.5 MB-
00:00-
60-
0-
0
...

期望的输出:

Summary of client activity for the last 24 hours
DomainNodenamePlatformTypeActivityData amountElapse timeAffectedFailedMedia     wait
-FILESYSTEM-ABSYNTHE-Linux x86-64-XFS-
BACKUP-
337.5 MB-
00:00-
60-
0-
0
...

Answer 1

使用 awk:

awk '/Summary of client activity for the last 24 hours/{p=1}p' file

或者 sed:

sed -n '/Summary of client activity for the last 24 hours/,$p' file

使用 awk 测试您的电子邮件示例(上面的 sed cmd 具有相同的输出):

kent$  cat f
...(Personal Part of the Email)...
...
The following clients have no associated schedule
NodeDomainContact
-KABA-FILESYSTEM-
-USTICA-FILESYSTEM-

Summary of client activity for the last 24 hours
DomainNodenamePlatformTypeActivityData amountElapse timeAffectedFailedMedia     wait
-FILESYSTEM-ABSYNTHE-Linux x86-64-XFS-
BACKUP-
337.5 MB-
00:00-
60-
0-
0
...

kent$  awk '/Summary of client activity for the last 24 hours/{p=1}p' f
Summary of client activity for the last 24 hours
DomainNodenamePlatformTypeActivityData amountElapse timeAffectedFailedMedia     wait
-FILESYSTEM-ABSYNTHE-Linux x86-64-XFS-
BACKUP-
337.5 MB-
00:00-
60-
0-
0
..