python - 使用 pdfminer.six 从 URL 打开 PDF

Question

背景:Python 3.7 & pdfminer.six

使用此处找到的信息:Exporting Data from PDFs with Python ，我有以下代码:

import io

from pdfminer.converter import TextConverter
from pdfminer.pdfinterp import PDFPageInterpreter
from pdfminer.pdfinterp import PDFResourceManager
from pdfminer.pdfpage import PDFPage

def extract_text_from_pdf(pdf_path):
    resource_manager = PDFResourceManager()
    fake_file_handle = io.StringIO()
    converter = TextConverter(resource_manager, fake_file_handle)
    page_interpreter = PDFPageInterpreter(resource_manager, converter)

    with open(pdf_path, 'rb') as fh:
        for page in PDFPage.get_pages(fh, 
                                      caching=True,
                                      check_extractable=True):
            page_interpreter.process_page(page)

        text = fake_file_handle.getvalue()

    # close open handles
    converter.close()
    fake_file_handle.close()

    if text:
        return text

if __name__ == '__main__':
    path = '../_pdfs/mypdf.pdf'
    print(extract_text_from_pdf(path))

这有效(耶!)，但我真正想做的是直接通过其 url 请求 pdf，而不是打开已预先保存到本地驱动器的 pdf。

我不知道我需要如何修改“with open”逻辑以从远程 url 调用，我也不确定对于最新版本的 Python(requests、urllib、urllib2、等等？)

我是 Python 的新手，所以请记住这一点(P.s. 我发现了其他关于此的问题，但我无能为力 - 可能是因为它们往往很老。)

任何帮助将不胜感激!谢谢!

Answer 1

我是这样解决的:

from io import StringIO, BytesIO
import urllib.request

from pdfminer.converter import TextConverter
from pdfminer.pdfinterp import PDFPageInterpreter, PDFResourceManager
from pdfminer.pdfpage import PDFPage

def extract_text_from_pdf_url(url, user_agent=None):
    resource_manager = PDFResourceManager()
    fake_file_handle = StringIO()
    converter = TextConverter(resource_manager, fake_file_handle)    

    if user_agent == None:
        user_agent = 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/83.0.4103.61 Safari/537.36'

    headers = {'User-Agent': user_agent}
    request = urllib.request.Request(url, data=None, headers=headers)

    response = urllib.request.urlopen(request).read()
    fb = BytesIO(response)

    page_interpreter = PDFPageInterpreter(resource_manager, converter)

    for page in PDFPage.get_pages(fb,
                                caching=True,
                                check_extractable=True):
        page_interpreter.process_page(page)


    text = fake_file_handle.getvalue()

    # close open handles
    fb.close()
    converter.close()   
    fake_file_handle.close()

    if text:
        # If document has instances of \xa0 replace them with spaces.
        # NOTE: \xa0 is non-breaking space in Latin1 (ISO 8859-1) & chr(160)
        text = text.replace(u'\xa0', u' ')

        return text