Python/Selenium - 无法点击 www.instagram.com 上的“接受 cookie”按钮

Question

我正在尝试使用 python selenium 登录 instagram。但我必须接受 cookie 才能继续。

这是我的代码

class InstaBot:
    def __init__(self, username, pw):
        self.driver = webdriver.Chrome()
        self.driver.get('https://www.instagram.com/')
        sleep(2)
 #this is the code that im trying to use, so to click the accept button 
self.driver.find_element_by_xpath("/html/body/div[2]/div/div/div/div[2]/button[1]").click() 
        self.driver.find_element_by_xpath("//input[@name=\"username\"]")\
            .send_keys(username)
        self.driver.find_element_by_xpath("//input[@name=\"password\"]")\
            .send_keys(pw)
        self.driver.find_element_by_xpath("//a[contains(text(), 'Log in')]")\
            .click()
        sleep(4)

问题是当它点击接受按钮时它什么也没做。有什么想法吗？

Answer 1

应该点击接受登录和接下来的两个元素。只需等待元素变为可点击，然后点击它即可。

WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Accept']"))).click()
#Your code
WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "#loginForm > div > div:nth-child(3) > button"))).click()  
WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Save Info']"))).click()
WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Turn On']"))).click()

导入

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait 
from selenium.webdriver.support import expected_conditions as EC