Python:在读取文件并对一行中的单词进行计数时，我想将 ""或 ' ' 之间的单词计算为一个单词

Question

我有一个文件，我必须在其中计算每一行中的单词数，但是有一个技巧，无论出现在 ' ' 还是 ""之间，都应该算作一个单词。

示例文件:

TopLevel  
    DISPLAY "In TopLevel. Starting to run program"  
    PERFORM OneLevelDown  
    DISPLAY "Back in TopLevel."  
    STOP RUN.

对于上述文件，每行的字数必须如下所示:

Line: 1 has: 1 words  
Line: 2 has: 2 words  
Line: 3 has: 2 words  
Line: 4 has: 2 words  
Line: 5 has: 2 words

但我得到如下:

Line: 1 has: 1 words  
Line: 2 has: 7 words  
Line: 3 has: 2 words  
Line: 4 has: 4 words  
Line: 5 has: 2 words

from os import listdir
from os.path import isfile, join

srch_dir = r'C:\Users\sagrawal\Desktop\File'

onlyfiles = [srch_dir+'\\'+f for f in listdir(srch_dir) if isfile(join(srch_dir, f))]

for i in onlyfiles:
index = 0
    with open(i,mode='r') as file:
        lst = file.readlines()
        for line in lst:
            cnt = 0
            index += 1
            linewrds=line.split()
            for lwrd in linewrds:
                if lwrd:
                    cnt = cnt +1
            print('Line:',index,'has:',cnt,' words')

Answer 1

如果您只有这种简单格式(没有嵌套引号或转义引号)，您可以使用简单的正则表达式:

lines = '''TopLevel  
    DISPLAY "In TopLevel. Starting to run program"  
    PERFORM OneLevelDown  
    DISPLAY "Back in TopLevel."  
    STOP RUN.'''.split('\n')

import re
counts = [len(re.findall(r'\'.*?\'|".*?"|\S+', l))
          for l in lines]
# [1, 2, 2, 2, 2]

如果没有，你必须写一个解析器