python - 从列表创建键值对

Question

我有以下列表:

[('0-N', '3-C'), ('3-C', '5-C'), ('3-C', '9-C'), ('9- C', '12-C')]

我想用列表中的键值对创建以下字典:

{'0-N':['3-C'],'3-C':['0-N','5-C','9-C'],'9-C': ['3-C','12-C'],'12-C':['9-C']}

我们将不胜感激任何建议或帮助。

Answer 1

使用collections.defaultdict :

from collections import defaultdict

lst = [('0-N', '3-C'), ('3-C', '5-C'), ('3-C', '9-C'), ('9-C', '12-C')]

dct = defaultdict(list)
for tup in lst:
    dct[tup[0]].append(tup[1])
    dct[tup[1]].append(tup[0])

dct = dict(dct)
print(dct)
{'0-N': ['3-C'], '3-C': ['0-N', '5-C', '9-C'], '5-C': ['3-C'], '9-C': ['3-C', '12-C'], '12-C': ['9-C']}