ruby-on-rails - 在controller中取一个param，转换成string类型，保存

Question

我有一个 ajax post 来创建一个新的 Meeting。我想在保存之前将字符串 meeting_time 转换为 Controller 中的日期时间格式。

我已经试过了，但它仍然将 meeting_time 保存为一个字符串:

def create

requestor = current_user
@meeting_with_params = meeting_params
@meeting_time = @meeting_with_params[:meeting_time]
@meeting_time = @meeting_time.to_datetime
@meeting_with_params[:meeting_time] = @meeting_time
#@meeting_with_params
@meeting = Meeting.new(@meeting_with_params)

respond_to do |format|
  if @meeting.save
    format.html { redirect_to home_url, notice: 'Your lex was successfully requested! Click Plan Meeting ' }
    format.json { render :show, status: :created, location: @meeting }
  else
    format.html { render :new }
    format.json { render json: @meeting.errors, status: :unprocessable_entity }
  end
end
end

传递的参数如下所示:

Started POST "/meetings" for 127.0.0.1 at 2016-10-31 11:45:44 -0400
Processing by MeetingsController#create as */*
  Parameters: {"meeting"=>{"requestor_id"=>"1", "requestee_id"=>"2", "meeting_time"=>"2016-10-18 22:10:00", "accepted"=>"false", "status"=>"Active", "location"=>"Black Forest Restaurant", "location_address"=>"733 Fulton St, Brooklyn, NY 11217"}}
  User Load (0.2ms)  SELECT  "users".* FROM "users" WHERE "users"."id" = ?  ORDER BY "users"."id" ASC LIMIT 1  [["id", 1]]
   (0.1ms)  begin transaction
  SQL (1.1ms)  INSERT INTO "meetings" ("requestor_id", "requestee_id", "meeting_time", "accepted", "location", "status", "location_address", "created_at", "updated_at") VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?)  [["requestor_id", 1], ["requestee_id", 2], ["meeting_time", "2016-10-18 22:10:00.000000"], ["accepted", "f"], ["location", "Black Forest Restaurant"], ["status", "Active"], ["location_address", "733 Fulton St, Brooklyn, NY 11217"], ["created_at", "2016-10-31 15:45:44.557266"], ["updated_at", "2016-10-31 15:45:44.557266"]]

然后在 .js 文件中调用 ajax:

$.ajax({
                url: '/meetings',
                type: 'POST',
                data: {
                    meeting: {
                        requestor_id: currentUserId,
                        requestee_id: requesteeId,
                        meeting_time: rubyDateTime,
                        accepted: false,
                        status: "Active",
                        location: meetingLocation,
                        location_address: meetingAddress
                    }
                },
                success: function(result)   {
                    createNotification(currentUserId, "Your meeting was successfully requested.");
                    location.reload();
                },
                error: function(err)    {
                    console.log(err);
                }
            })

如何在创建 Controller 中拉出meeting_time，并在保存前将其更改为datetime？

谢谢!!

****更新我知道它没有正确保存，因为我还有一种方法可以将今天的日期与 meeting_time 进行比较，如果已经过去，则进行一些操作。直接保存到数据库时，它会识别已经过去的时间。当通过 POST 保存时，使用完全相同的字符串，它不会因为它比较 2 种不同的类型。对比 Controller :

def requestor_review_meeting
        @past_meetings = Meeting.where('meeting_time <= ? AND requestor_id= ? AND status = ? AND requestor_score < ?', DateTime.current, current_user, "Active", 1).order('meeting_time asc');
        render json: @past_meetings

end

在控制台中:

 > meeting_time
 => Tue, 18 Oct 2016 22:10:00 UTC +00:00 
2.1.2 :012 > meeting_time.class
 => ActiveSupport::TimeWithZone 
2.1.2 :013 > meeting_time.is_a?(DateTime)
 => false 
2.1.2 :015 > meeting_time.is_a?(Time)
=> true 

Answer 1

ActiveRecord 会自动对所有输入进行类型转换，以便它们与数据库架构相匹配。因此，即使允许您将 meeting_time 保存为字符串，它也会在加载时将其转换为日期时间。如果您有兴趣，可以阅读更多 here