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Xtext 独立和验证

转载 作者:行者123 更新时间:2023-12-05 02:17:47 25 4
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构建一个解析文件的独立程序,我使用了第一个选项 http://www.davehofmann.de/?p=101

定义了一个验证,如果文本不是以大写字母开头,则会给出错误(eclipse 中的红色下划线)。

独立解析器不会给出未通过验证的输入文件的错误。我怎样才能要求独立实现也验证验证?

更新 1

包含checkResource用于解析语法的类:

class XtextParser {
@Inject
private IParser parser;
new() {
var injector = new MyDslStandaloneSetup().
createInjectorAndDoEMFRegistration();
injector.injectMembers(this)
}
def EObject parse(Reader reader) throws IOException {
var result = parser.parse(reader)
if (result.hasSyntaxErrors()) {
throw new ParseException("Provided input contains syntax errors.")
}
var resource = result.getRootASTElement().eResource()
//resource is null
//checkResource(resource)
return result.getRootASTElement();
}
@Inject IResourceValidator resourceValidator

def void checkResource(Resource resource) {
val issues = resourceValidator.validate(resource,
CheckMode.ALL, CancelIndicator.NullImpl)
for (issue : issues) {
switch issue.severity {
case ERROR:
println("ERROR: " + issue.message)
case WARNING:
println("WARNING: " + issue.message)
}
}
}
}

最佳答案

如果你不调用验证器,它就不会验证。所以叫它(伪代码)

@Inject IResourceValidator resourceValidator

def void checkResource(Resource resource) {
val issues = resourceValidator.validate(resource,
CheckMode.ALL, CancelIndicator.NullImpl)
for (issue: issues) {
switch issue.severity {
case ERROR:
println("ERROR: " + issue.message)
case WARNING:
println("WARNING: " + issue.message)
}
}
}

因为你发的博文对如何调用很含糊

import java.io.IOException;
import java.util.List;

import org.eclipse.emf.common.util.URI;
import org.eclipse.emf.ecore.resource.Resource;
import org.eclipse.emf.ecore.resource.ResourceSet;
import org.eclipse.xtext.util.CancelIndicator;
import org.eclipse.xtext.validation.CheckMode;
import org.eclipse.xtext.validation.IResourceValidator;
import org.eclipse.xtext.validation.Issue;

import com.google.inject.Injector;

public class Main {

public static void main(String[] args) throws IOException {
Injector injector = new MyDslStandaloneSetup().createInjectorAndDoEMFRegistration();
ResourceSet rs = injector.getInstance(ResourceSet.class);
Resource resource = rs.getResource(URI.createURI("test.mydsl"), true);
resource.load(null);
IResourceValidator validator = injector.getInstance(IResourceValidator.class);
List<Issue> issues = validator.validate(resource,
CheckMode.ALL, CancelIndicator.NullImpl);
for (Issue issue: issues) {
switch (issue.getSeverity()) {
case ERROR:
System.out.println("ERROR: " + issue.getMessage());
case WARNING:
System.out.println("WARNING: " + issue.getMessage());
}
}
}

}

关于Xtext 独立和验证,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47110291/

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