gpt4 book ai didi

java - 如何使用 java 代码使用 client_credentials 获取访问 token ?

转载 作者:行者123 更新时间:2023-12-05 02:15:19 25 4
gpt4 key购买 nike

我有一些 API 需要访问 token 才能获得响应。在 postman 中,我们使用 OAuth 2.0 通过提供客户端用户名和密码来获取访问 token 。以类似的方式,我想获取新的访问 token 。

这是我到目前为止尝试过的示例代码。

import java.io.*;
import java.net.URL;
import java.net.URLEncoder;
import java.util.Map;
import java.lang.reflect.Type;
import javax.net.ssl.HttpsURLConnection;

// Google Gson Libraries used for Json Parsing
import com.google.gson.Gson;
import com.google.gson.reflect.TypeToken;

public class AuthGoogle {

/**
* @param args
* @throws IOException
*/
public static void main(String[] args) throws IOException {
// TODO Auto-generated method stub
String grantType = "client_credentials";
String applicationID = "application";
String username = "username";
String password = "password";
String url = "url_link";
HttpsURLConnection httpConn = null;
BufferedReader in = null;

try {

// Create the data to send
StringBuilder data = new StringBuilder();
data.append("grant_type=" + URLEncoder.encode(grantType, "UTF-8"));
data.append("&client_id=" + URLEncoder.encode(applicationID, "UTF-8"));
data.append("&username=" + URLEncoder.encode(username, "UTF-8"));
data.append("&password=" + URLEncoder.encode(password, "UTF-8"));

// Create a byte array of the data to be sent
byte[] byteArray = data.toString().getBytes("UTF-8");

// Setup the Request
URL request = new URL(null, url, new sun.net.www.protocol.https.Handler());
httpConn = (HttpsURLConnection)request.openConnection();
httpConn.setRequestMethod("POST");
httpConn.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
httpConn.setRequestProperty("Content-Length", "" + byteArray.length);
httpConn.setDoOutput(true);

// Write data
OutputStream postStream = httpConn.getOutputStream();
postStream.write(byteArray, 0, byteArray.length);
postStream.close();

// Send Request & Get Response
InputStreamReader reader = new InputStreamReader(httpConn.getInputStream());
in = new BufferedReader(reader);

// Get the Json reponse containing the Access Token
String json = in.readLine();
System.out.println("Json String = " + json);

// Parse the Json response and retrieve the Access Token
Gson gson = new Gson();
Type mapType = new TypeToken<Map<String,String>>(){}.getType();
Map<String,String> ser = gson.fromJson(json, mapType);
String accessToken = ser.get("access_token");
System.out.println("Access Token = " + accessToken);

} catch (java.io.IOException e) {

// This exception will be raised if the server didn't return 200 - OK
// Retrieve more information about the error
System.out.println(e.getMessage());

} finally {

// Be sure to close out any resources or connections
if (in != null) in.close();
if (httpConn != null) httpConn.disconnect();
}
}

}

我得到的输出是 Connection refused: connect.

我试过的另一个代码是:-

import org.apache.oltu.oauth2.client.OAuthClient;
import org.apache.oltu.oauth2.client.URLConnectionClient;
import org.apache.oltu.oauth2.client.request.OAuthClientRequest;
import org.apache.oltu.oauth2.client.response.OAuthJSONAccessTokenResponse;
import org.apache.oltu.oauth2.common.OAuth;
import org.apache.oltu.oauth2.common.message.types.GrantType;

import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
import org.apache.commons.codec.binary.Base64;

public class OltuJavaClient {

public static final String TOKEN_REQUEST_URL = "url_link";
public static final String CLIENT_ID = "client_id";
public static final String CLIENT_SECRET = "client_pass";

public static void main(String[] args) {
try {
OAuthClient client = new OAuthClient(new URLConnectionClient());

OAuthClientRequest request =
OAuthClientRequest.tokenLocation(TOKEN_REQUEST_URL)
.setGrantType(GrantType.CLIENT_CREDENTIALS)
.setClientId(CLIENT_ID)
.setClientSecret(CLIENT_SECRET)
// .setScope() here if you want to set the token scope
.buildQueryMessage();
request.addHeader("Accept", "application/json");
request.addHeader("Content-Type", "application/json");
request.addHeader("Authorization", base64EncodedBasicAuthentication());

String token = client.accessToken(request, OAuth.HttpMethod.POST, OAuthJSONAccessTokenResponse.class).getAccessToken();
System.out.println(token.toString());

} catch (Exception exn) {
exn.printStackTrace();
}
}

private static String base64EncodedBasicAuthentication() {
// TODO Auto-generated method stub
return null;
}
}

这里我收到这个错误:- OAuthProblemException{error='unsupported_response_type', description='Invalid response!响应主体不是应用程序/json 编码', uri='null', state='null', scope='null', redirectUri='null', responseStatus=0, parameters={}}

我们可以这样做吗?任何线索将不胜感激。

最佳答案

使用 JAVA 11 java.net.http 获取访问 token 的最佳方式。

示例代码如下:

//Cliend id and client secret
var keys = "clientid goes here:Client secret goes here";
var URL = "http://localhost:8080/api/token"

HashMap<String, String> parameters = new HashMap<>();
parameters.put("grant_type", "client_credentials");
String form = parameters.keySet().stream()
.map(key -> key + "=" + URLEncoder.encode(parameters.get(key), StandardCharsets.UTF_8))
.collect(Collectors.joining("&"));

String encoding = Base64.getEncoder().encodeToString(keys.getBytes());
HttpClient client = HttpClient.newHttpClient();

HttpRequest request = HttpRequest.newBuilder().uri(URI.create(url))
.headers("Content-Type", "application/x-www-form-urlencoded", "Authorization", "Basic "+encoding)
.POST(BodyPublishers.ofString(form)).build();
HttpResponse<?> response = client.send(request, BodyHandlers.ofString());
System.out.println(response.statusCode() + response.body().toString());

关于java - 如何使用 java 代码使用 client_credentials 获取访问 token ?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/52144721/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com