javascript - 如何使用 lodash 比较两个数组(顺序很重要)

Question

var arr1=[3,4,5,6,7,1,9];
var arr2=[1,3,4,6,7,5,9];

我想比较 arr2 和 arr1。但是方法 difference() 和 intersection() 似乎只能查找两个数组是否具有相同的元素。我想逐点比较这两个数组，如 arr1[0] 到 arr2[0]、arr1[1] 到 arr2[1]。它应该显示:

intersection: 6,7,9
difference: 1,3,4,5

我怎样才能做到这一点？

Answer 1

您可以在 lodash 中执行此操作，方法是压缩两个数组、过滤，然后取每对数组的最后一项。交集的比较器是该对相等。差异的比较器是该对不相等。

const arr1 = [3,4,5,6,7,1,9];
const arr2 = [1,3,4,6,7,5,9];

const compare = (comperator) => (arr1, arr2) => 
  _.zip(arr1, arr2)
  .filter(comperator)
  .map(_.last);

const eq = _.spread(_.eq);

const intersection = compare(eq);
  
const difference = compare(_.negate(eq));

console.log('intersection ', intersection(arr1, arr2));
console.log('difference ', difference(arr1, arr2));

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