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python - 同时替换 pandas df 中的多个值

转载 作者:行者123 更新时间:2023-12-05 02:07:58 24 4
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我正在尝试同时替换 pandas df 中的值。看起来该函数连续执行此操作,因此我替换的值最终被覆盖。使用下面的 X == Left,我想替换 A-DB-CC-B D-A。如果我只执行其中一个调用,效果会很好,但当我执行所有四个调用时,它就不行了。以下是我的尝试:

import pandas as pd

df = pd.DataFrame({
'X' : ['Left','Left','Left','Left','Right','Right','Right','Right'],
'Y' : ['A','B','C','D','A','B','C','D'],
})

尝试 1:

df[(df['X'] == 'Left') & (df['Y'] == 'A')] = df['Y'].map({'A': 'D'})
df[(df['X'] == 'Left') & (df['Y'] == 'B')] = df['Y'].map({'B': 'C'})
df[(df['X'] == 'Left') & (df['Y'] == 'C')] = df['Y'].map({'C': 'B'})
df[(df['X'] == 'Left') & (df['Y'] == 'D')] = df['Y'].map({'D': 'A'})

输出:

       X  Y
0 D D
1 C C
2 B B
3 A A
4 Right A
5 Right B
6 Right C
7 Right D

尝试 2:

df.loc[(df['X'] == 'Left') & (df['Y'] == 'A'), 'Y'] = 'D'
df.loc[(df['X'] == 'Left') & (df['Y'] == 'B'), 'Y'] = 'C'
df.loc[(df['X'] == 'Left') & (df['Y'] == 'C'), 'Y'] = 'B'
df.loc[(df['X'] == 'Left') & (df['Y'] == 'D'), 'Y'] = 'A'

输出:

       X  Y
0 Left A
1 Left B
2 Left B
3 Left A
4 Right A
5 Right B
6 Right C
7 Right D

预期输出:

       X  Y
0 Left D
1 Left C
2 Left B
3 Left A
4 Right A
5 Right B
6 Right C
7 Right D

最佳答案

替换一次:

df.Y.update(df.loc[df['X'] == 'Left','Y'].replace({'A': 'D','B': 'C','C': 'B','D': 'A'}))
df
X Y
0 Left D
1 Left C
2 Left B
3 Left A
4 Right A
5 Right B
6 Right C
7 Right D

关于python - 同时替换 pandas df 中的多个值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61378187/

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