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scala - java.lang.String is not a valid external type for schema of int error in creating spark 数据帧

转载 作者:行者123 更新时间:2023-12-05 02:06:14 30 4
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我只是尝试用 spark 制作数据框。我只是尝试制作如下代码。

首先,我导入如下

import org.apache.spark.sql.types._
import org.apache.spark.storage.StorageLevel
import scala.io.Source
import scala.collection.mutable.HashMap
import java.io.File
import org.apache.spark.sql.Row
import scala.collection.mutable.ListBuffer
import org.apache.spark.util._
import org.apache.spark.sql.types.IntegerType`

然后,我尝试为数据框制作 Row 和 Schema,如下所示。

val Employee = Seq(Row("Kim","Seoul","1000000"),Row("Lee","Busan","2000000"),Row("Park","Jeju","3000000"),Row("Jeong","Daejon","3400000"))

val EmployeeSchema = List(StructField("Name", StringType, true), StructField("City", StringType, true), StructField("Salary", IntegerType, true))

val EmpDF = spark.createDataFrame(spark.sparkContext.parallelize(Employee),StructType(EmployeeSchema))

最后,我尝试查看数据框是否可以使用

EmpDF.show

我得到如下错误

    ERROR Executor: Exception in task 2.0 in stage 1.0 (TID 3)
java.lang.RuntimeException: Error while encoding: java.lang.RuntimeException:
java.lang.String is not a valid external type for schema of int
if (assertnotnull(input[0, org.apache.spark.sql.Row, true]).isNullAt) null else staticinvoke(class org.apache.spark.unsafe.types.UTF8String, StringType, fromString, validateexternaltype(getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true]), 0, Name), StringType), true, false) AS Name#0
if (assertnotnull(input[0, org.apache.spark.sql.Row, true]).isNullAt) null else staticinvoke(class org.apache.spark.unsafe.types.UTF8String, StringType, fromString, validateexternaltype(getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true]), 1, City), StringType), true, false) AS City#1
if (assertnotnull(input[0, org.apache.spark.sql.Row, true]).isNullAt) null else validateexternaltype(getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true]), 2, Salary), IntegerType) AS Salary#2
at org.apache.spark.sql.catalyst.encoders.ExpressionEncoder.toRow(ExpressionEncoder.scala:292)
at org.apache.spark.sql.SparkSession$$anonfun$4.apply(SparkSession.scala:594)
at org.apache.spark.sql.SparkSession$$anonfun$4.apply(SparkSession.scala:594)
at scala.collection.Iterator$$anon$11.next(Iterator.scala:410)
at scala.collection.Iterator$$anon$11.next(Iterator.scala:410)
at org.apache.spark.sql.catalyst.expressions.GeneratedClass$GeneratedIteratorForCodegenStage1.processNext(Unknown Source)
at org.apache.spark.sql.execution.BufferedRowIterator.hasNext(BufferedRowIterator.java:43)
at org.apache.spark.sql.execution.WholeStageCodegenExec$$anonfun$13$$anon$1.hasNext(WholeStageCodegenExec.scala:636)
at org.apache.spark.sql.execution.SparkPlan$$anonfun$2.apply(SparkPlan.scala:255)
at org.apache.spark.sql.execution.SparkPlan$$anonfun$2.apply(SparkPlan.scala:247)
at org.apache.spark.rdd.RDD$$anonfun$mapPartitionsInternal$1$$anonfun$apply$24.apply(RDD.scala:858)
at org.apache.spark.rdd.RDD$$anonfun$mapPartitionsInternal$1$$anonfun$apply$24.apply(RDD.scala:858)
at org.apache.spark.rdd.MapPartitionsRDD.compute(MapPartitionsRDD.scala:52)
at org.apache.spark.rdd.RDD.computeOrReadCheckpoint(RDD.scala:346)
at org.apache.spark.rdd.RDD.iterator(RDD.scala:310)
at org.apache.spark.rdd.MapPartitionsRDD.compute(MapPartitionsRDD.scala:52)
at org.apache.spark.rdd.RDD.computeOrReadCheckpoint(RDD.scala:346)
at org.apache.spark.rdd.RDD.iterator(RDD.scala:310)
at org.apache.spark.scheduler.ResultTask.runTask(ResultTask.scala:90)
at org.apache.spark.scheduler.Task.run(Task.scala:123)
at org.apache.spark.executor.Executor$TaskRunner$$anonfun$10.apply(Executor.scala:408)
at org.apache.spark.util.Utils$.tryWithSafeFinally(Utils.scala:1360)
at org.apache.spark.executor.Executor$TaskRunner.run(Executor.scala:414)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624)
at java.lang.Thread.run(Thread.java:748)
Caused by: java.lang.RuntimeException: java.lang.String is not a valid external type for schema of int
at org.apache.spark.sql.catalyst.expressions.GeneratedClass$SpecificUnsafeProjection.If_0$(Unknown Source)
at org.apache.spark.sql.catalyst.expressions.GeneratedClass$SpecificUnsafeProjection.writeFields_0_1$(Unknown Source)
at org.apache.spark.sql.catalyst.expressions.GeneratedClass$SpecificUnsafeProjection.apply(Unknown Source)
at org.apache.spark.sql.catalyst.encoders.ExpressionEncoder.toRow(ExpressionEncoder.scala:289)
... 25 more
20/07/12 16:32:51 ERROR Executor: Exception in task 0.0 in stage 1.0 (TID 1)
java.lang.RuntimeException: Error while encoding: java.lang.RuntimeException: java.lang.String is not a valid external type for schema of int
if (assertnotnull(input[0, org.apache.spark.sql.Row, true]).isNullAt) null else staticinvoke(class org.apache.spark.unsafe.types.UTF8String, StringType, fromString, validateexternaltype(getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true]), 0, Name), StringType), true, false) AS Name#0
if (assertnotnull(input[0, org.apache.spark.sql.Row, true]).isNullAt) null else staticinvoke(class org.apache.spark.unsafe.types.UTF8String, StringType, fromString, validateexternaltype(getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true]), 1, City), StringType), true, false) AS City#1
if (assertnotnull(input[0, org.apache.spark.sql.Row, true]).isNullAt) null else validateexternaltype(getexternalrowfield(assertnotnull(input[0, org.apache.spark.sql.Row, true]), 2, Salary), IntegerType) AS Salary#2
at org.apache.spark.sql.catalyst.encoders.ExpressionEncoder.toRow(ExpressionEncoder.scala:292)
at org.apache.spark.sql.SparkSession$$anonfun$4.apply(SparkSession.scala:594)
at org.apache.spark.sql.SparkSession$$anonfun$4.apply(SparkSession.scala:594)
at scala.collection.Iterator$$anon$11.next(Iterator.scala:410)
at scala.collection.Iterator$$anon$11.next(Iterator.scala:410)
at org.apache.spark.sql.catalyst.expressions.GeneratedClass$GeneratedIteratorForCodegenStage1.processNext(Unknown Source)
at org.apache.spark.sql.execution.BufferedRowIterator.hasNext(BufferedRowIterator.java:43)
at org.apache.spark.sql.execution.WholeStageCodegenExec$$anonfun$13$$anon$1.hasNext(WholeStageCodegenExec.scala:636)
at org.apache.spark.sql.execution.SparkPlan$$anonfun$2.apply(SparkPlan.scala:255)
at org.apache.spark.sql.execution.SparkPlan$$anonfun$2.apply(SparkPlan.scala:247)
at org.apache.spark.rdd.RDD$$anonfun$mapPartitionsInternal$1$$anonfun$apply$24.apply(RDD.scala:858)
at org.apache.spark.rdd.RDD$$anonfun$mapPartitionsInternal$1$$anonfun$apply$24.apply(RDD.scala:858)
at org.apache.spark.rdd.MapPartitionsRDD.compute(MapPartitionsRDD.scala:52)
at org.apache.spark.rdd.RDD.computeOrReadCheckpoint(RDD.scala:346)
at org.apache.spark.rdd.RDD.iterator(RDD.scala:310)
at org.apache.spark.rdd.MapPartitionsRDD.compute(MapPartitionsRDD.scala:52)
at org.apache.spark.rdd.RDD.computeOrReadCheckpoint(RDD.scala:346)
at org.apache.spark.rdd.RDD.iterator(RDD.scala:310)
at org.apache.spark.scheduler.ResultTask.runTask(ResultTask.scala:90)
at org.apache.spark.scheduler.Task.run(Task.scala:123)
at org.apache.spark.executor.Executor$TaskRunner$$anonfun$10.apply(Executor.scala:408)
at org.apache.spark.util.Utils$.tryWithSafeFinally(Utils.scala:1360)
at org.apache.spark.executor.Executor$TaskRunner.run(Executor.scala:414)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624)
at java.lang.Thread.run(Thread.java:748)

我该如何解决这个问题?

我已经尝试过如下导入

    import org.apache.spark.serializer.KryoSerializer
import org.apache.spark.serializer.Serializer

但现在它显示错误

ERROR Executor: Exception in task 2.0 in stage 5.0 (TID 13)

最佳答案

Error while encoding: java.lang.RuntimeException: java.lang.String is not a valid external type for schema of int 是由于定义的模式和实际数据之间的类型不匹配 "Jeong","Daejon","3400000"-> (string,string,string)。但您在架构中指定为 (String,String,Integer)

更新特定于整数类型的代码 1:

import org.apache.spark.sql.types._
import org.apache.spark.storage.StorageLevel
import scala.io.Source
import scala.collection.mutable.HashMap
import java.io.File
import org.apache.spark.sql.Row
import scala.collection.mutable.ListBuffer
import org.apache.spark.util._
import org.apache.spark.sql.types._

val Employee = Seq(Row("Kim","Seoul",1000000),Row("Lee","Busan",2000000),Row("Park","Jeju",3000000),Row("Jeong","Daejon",3400000))

val EmployeeSchema = List(StructField("Name", StringType, true), StructField("City", StringType, true), StructField("Salary", IntegerType, true))

val EmpDF = spark.createDataFrame(spark.sparkContext.parallelize(Employee),StructType(EmployeeSchema))
EmpDF.show()
/*+-----+------+-------+
| Name| City| Salary|
+-----+------+-------+
| Kim| Seoul|1000000|
| Lee| Busan|2000000|
| Park| Jeju|3000000|
|Jeong|Daejon|3400000|
+-----+------+-------+*/

特定于字符串类型的更新代码:

import org.apache.spark.sql.types._
import org.apache.spark.storage.StorageLevel
import scala.io.Source
import scala.collection.mutable.HashMap
import java.io.File
import org.apache.spark.sql.Row
import scala.collection.mutable.ListBuffer
import org.apache.spark.util._
import org.apache.spark.sql.types._

val Employee = Seq(Row("Kim","Seoul","1000000"),Row("Lee","Busan","2000000"),Row("Park","Jeju","3000000"),Row("Jeong","Daejon","3400000"))

val EmployeeSchema = List(StructField("Name", StringType, true), StructField("City", StringType, true), StructField("Salary", StringType, true))

val EmpDF = spark.createDataFrame(spark.sparkContext.parallelize(Employee),StructType(EmployeeSchema))
EmpDF.show()
/*+-----+------+-------+
| Name| City| Salary|
+-----+------+-------+
| Kim| Seoul|1000000|
| Lee| Busan|2000000|
| Park| Jeju|3000000|
|Jeong|Daejon|3400000|
+-----+------+-------+*/

关于scala - java.lang.String is not a valid external type for schema of int error in creating spark 数据帧,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62858613/

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