Javascript : Filter list with element contains

Question

我有以下对象-

[
{
 employeeId:1
 employeeName:"ABC"
},
{
 employeeId:2
 employeeName:"ABD"
},
{
 employeeId:3
 employeeName:"FEW"
},
{
 employeeId:4
 employeeName:"JKABL"
},]

我想根据 employeeName 上提供的单词过滤此列表。

例如。如果提供员工姓名单词:- AB；然后它应该过滤掉-

[
    {
     employeeId:1
     employeeName:"ABC"
    },
    {
     employeeId:2
     employeeName:"ABD"
    },
    {
     employeeId:4
     employeeName:"JKABL"
    },]

因为 EmployeeIds 1,2 和 4 包含带 AB 的员工姓名。

为此我尝试了-

object.filter(x=>x.employeeName.indexOf("AB")>-1)

每次都返回空数组。

我试过的第二种方法-

   var filteredObject=object.map(x=>{
 if(x.employeeName.indexOf("AB")>-1)
  return x;
});

每次都返回 undefined。

Answer 1

您可以定义一个自定义函数，该函数使用 includes 进行过滤:

const data = [
  {
    employeeId: 1,
    employeeName: 'ABC',
  },
  {
    employeeId: 2,
    employeeName: 'ABD',
  },
  {
    employeeId: 3,
    employeeName: 'FEW',
  },
  {
    employeeId: 4,
    employeeName: 'JKABL',
  },
];

const filterName = (search) => {
  return data.filter((value) => value.employeeName.includes(search));
};

console.log(filterName('AB'));