javascript - 在对象数组中计算胜利、游戏和游戏类型并创建对象对象

Question

我确信已经有一个答案以及一个“简单”的解决方案，但我在过去一小时内没有找到任何东西。

所以我有这个对象:

[
  {
    "win": false,
    "switched": false
  },
  {
    "win": false,
    "switched": false
  },
  {
    "win": true,
    "switched": true
  },
  {
    "win": true,
    "switched": true
  }
]

它显示了四场 monty-hall 游戏的结果。我想从此数组创建一个具有以下结构的对象:

{
    switched: {
        played: 2,
        won: 2
    },
    put: {
        played: 2,
        lost: 2
    }
}

所以实际上如果上部数组中的对象有 switched: true 我想将 switched["played"] 的值增加 1 并且它还有 won: true 我想将 switched["won"] 键的值也增加一。 switched: false 反之亦然，我希望将结果对象中的所有内容都放在 put 键下。

我用 reduce 尝试了一些相当尴尬的方法，但我认为必须有一种“更简单”的方法(我的方法根本不起作用......)

Answer 1

const items = [{
    win: false,
    switched: false
  },
  {
    win: false,
    switched: false
  },
  {
    win: true,
    switched: true
  },
  {
    win: true,
    switched: true
  }
];

const res = items.reduce(
  (acc, cur) => {
    // If your current item is switched
    return cur["switched"]
      ? { // ... deal with the switched part, leave the rest as is
          ...acc,
          switched: {
            played: acc.switched.played + 1, // increase the played counter by 1, based on whatever your accumulator currently has
            won: acc.switched.won + Number(cur.win) // cast your win property to number (true -> 1, false -> 0) and increase accordngily
          }
        }
      : { // ... otherwise deal with the put part, leave the rest as is
          ...acc,
          put: {
            played: acc.put.played + 1,
            lost: acc.put.lost + Number(!cur.win) // negate your win so that it reflects a loss, cast to number and increase accordingly
          }
        };
  },
  // Initialize your accumulator
  {
    switched: {
      played: 0,
      won: 0
    },
    put: {
      played: 0,
      lost: 0
    }
  }
);

console.log(res);