Python如何在没有其他月份日期的情况下迭代月份

Question

我正在尝试将 11 月的所有日期作为 11 月的日期:

import calendar

calen = calendar.Calendar()        
calen_iter = calen.itermonthdates(2017,11)

for c in calen_iter: 
    print (c)

我得到以下输出:

2017-10-30
2017-10-31
2017-11-01
2017-11-02
2017-11-03
<snipped lots of correct output>
2017-11-28
2017-11-29
2017-11-30
2017-12-01
2017-12-02
2017-12-03

---

我不想要这些日期 - 为什么会出现它们？

2017-10-30
2017-10-31
2017-12-01
2017-12-02
2017-12-03

Answer 1

这是设计使然，请参阅help(calen.itermonthdays)(强调我的):

itermonthdates(year, month) method of calendar.Calendar instance

Return an iterator for one month. The iterator will yield datetime.date values and will always iterate through complete weeks, so it will yield dates outside the specified month.

添加条件以过滤掉其他月份的天数:

for c in calen_iter: 
    if c.month == 11:
        print(c)

或者更简洁地使用列表理解:

days_of_november = [d for d in calen.itermonthdates(2017, 11) if d.month == 11]