listview - 如何使用 x :Name of items in listView at codebehind?

Question

有什么方法可以在 xamarin.forms 的代码后面的 ListView 中使用 x:Stacklayout 的名称？

 <ListView HasUnevenRows="true" HeightRequist="{Binding ListHeight}">
 <ListView.ItemTemplate>
      <DataTemplate>
          <ViewCell>
             <StackLayout>
                 <StackLayout x:Name="btnStack/>
             </StackLayout>
          </ViewCell>
     </DataTemplate>
</ListView.ItemTemplate>
</ListView>

如何在代码隐藏中使用btnStack？

Answer 1

为了能够按名称和您喜欢的任何方式访问模板化元素，请创建一个自定义 View ，将您用作单元格。在单元格的代码隐藏中，您将能够通过名称访问所有内容。您的初始 parent 列表现在如下所示:

<ListView HasUnevenRows="true" HeightRequest="{Binding ListHeight}">
 <ListView.ItemTemplate>
      <DataTemplate>
          <user:MyViewCell/>
     </DataTemplate>
</ListView.ItemTemplate>
</ListView>

您全新的手机将如下所示:

XAML:

   <?xml version="1.0" encoding="UTF-8"?>
    <ViewCell xmlns="http://xamarin.com/schemas/2014/forms" 
             xmlns:x="http://schemas.microsoft.com/winfx/2009/xaml"
             x:Class="YourNameSpace.MyViewCell">
    <StackLayout x:Name="btnStack" Spacing="0">
        <Label x:Name="txtEvenMore"/>
    </StackLayout>

    </ViewCell>

代码:

namespace YourNameSpace
{
    [XamlCompilation(XamlCompilationOptions.Compile)]
    public partial class MyViewCell
    {
        public MyViewCell()
        {
            InitializeComponent();

            //you can init your cells here
            InitCell(); //this is just for demo
        }

        public void InitCell()
        {
            //i can access my stack:
            btnStack.BackgroundColor = Color.Red;
            //and even more
            txtEvenMore.Text = "By name? Yes! :)";
        }

        //Now not for demo but in the real world:
        //We can set content according to your data from ItemsSource
        //This will act when you set your ListView ItemsSource to something valid
        protected override void OnBindingContextChanged()
        {
            SetupCell();
            base.OnBindingContextChanged();
        }

        public void SetupCell()
        {
            //use data from ItemsSource
            var item = BindingContext as YourItemClass;
            if (item == null) return;

            txtEvenMore.Text = item.SomeTextProperty;
            //etc.. :)
        }

   }
 }

祝你好运! :)