R:按一天中的时间缩短日期时间

Question

我有一个带有 POSIXct 日期时间的 data_frame。我现在想创建一个变量，将这些日期时间切割成时间段:1 -- [00:00:00, 08:00:00), 2 -- [08:00:00, 17:00:00) , 3 -- [17:00:00, 18:30:00), 4 -- [18:30:00, 00:00:00).

这是一些示例数据:

df_times = data_frame(
  datetime = seq.POSIXt(
    from = as.POSIXct(strftime("2016-01-01 00:00:00", format = "%Y-%m-%d :%H:%M:%S")),
    by = "min",
    length.out = 100000
  ),
  value = rnorm(100000)
)

这是预期的输出:

> df_times
# A tibble: 100,000 × 3
              datetime      value  band
                <dttm>      <dbl> <dbl>
1  2016-01-01 00:00:00  0.5855288     1
2  2016-01-01 00:01:00  0.7094660     1
3  2016-01-01 00:02:00 -0.1093033     1
4  2016-01-01 00:03:00 -0.4534972     1
5  2016-01-01 00:04:00  0.6058875     1
6  2016-01-01 00:05:00 -1.8179560     1
7  2016-01-01 00:06:00  0.6300986     1
8  2016-01-01 00:07:00 -0.2761841     1
9  2016-01-01 00:08:00 -0.2841597     1
10 2016-01-01 00:09:00 -0.9193220     1
# ... with 99,990 more rows

我已经尝试过 cut.POSIXt 但坚持要跟踪日期。理想的解决方案将使用 dplyr::recode 或 forcats::。

Answer 1

这是我认为直接将问题的意图转化为代码的解决方案:

set.seed(12345)

# create a dataset
df_times = data_frame(
  datetime = seq.POSIXt(
    from = as.POSIXct("2016-01-01 00:00:00", format = "%Y-%m-%d %H:%M:%S"),
    by = "min",
    length.out = 100000
  ),
  value = rnorm(100000)
) %>% 
  mutate(
    time = times(format(datetime, "%H:%M:%S")),
    cut(
      time,
      breaks = times(c(
        "00:00:00", 
        "08:00:00", 
        "17:00:00",
        "18:30:00",
        "23:59:59"
      )),
      labels = c(
        "1",
        "2",
        "3",
        "4"
      ),
      include.lowest = TRUE,
      right = FALSE
    )
  )