RxJS:将 void 值作为初始值发出的正确方法是什么？

Question

在the example你可以看到，如果你需要一个 void 类型的流的初始值，它看起来是不正确的。

import { of, fromEvent, concat, Subject } from "rxjs";
import { map, switchMap, take, finalize } from "rxjs/operators";

let sequence = 1;
const trigger = new Subject<void>();
const source = concat(
  of(""), // is there any way to make it more pretty?
  trigger
).pipe(
  switchMap(() =>
    fromEvent(document, "click").pipe(
      take(3),
      finalize(() => {
        sequence++;
        trigger.next();
      })
    )
  ),
  map(
    ({ clientY }: MouseEvent) => `sequence: ${sequence} clientY: ${clientY}!`
  )
);

source.subscribe(x => console.log(x));

Answer 1

不确定是否有比这“更漂亮”的解决方案:

const source =
  trigger.pipe(
    startWith(undefined as void),
    switchMap(...),
    ...
  );