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R - 将 df 或矩阵的每一行与一个向量相乘

转载 作者:行者123 更新时间:2023-12-05 01:32:18 24 4
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虽然看起来很简单,但我做不到。我想将矩阵(或数据帧或数据表)b 中的每一行与向量 a 相乘。

a <- data.table(t(1:4))
b <- matrix(data=2, nrow=3, ncol=4)

期望的输出(矩阵、数据框或数据表形式):

     [,1] [,2] [,3] [,4]
[1,] 2 4 6 8
[2,] 2 4 6 8
[3,] 2 4 6 8

谁能帮助我如何(有效地)做到这一点?

最佳答案

b*rep(unlist(a),each=nrow(b))
# [,1] [,2] [,3] [,4]
# [1,] 2 4 6 8
# [2,] 2 4 6 8
# [3,] 2 4 6 8

或者只是b*rep(a,each=nrow(b))如果你定义 a <- 1:4

它只是一个向量化的元素明智的乘法,没有来自 rep 的转换.

编辑:

似乎是 rep 拖慢了我的解决方案。这是一个基准测试,其中我包含一个带有预计算代表的选项,以及对扫描选项的一些改进(仅从源代码中获取相关部分)。

a <- data.table(t(1:200))
b <- matrix(data=2, nrow=100000, ncol=200)

a_vec <- unlist(a)
rep_a <- rep(a_vec,each=nrow(b))
microbenchmark::microbenchmark(
mkr1 = a[,lapply(.SD,function(x)(x*b[,x]))],
mkr2 = t(t(b) * (as.matrix(a)[1,])),
mkr_update = a[,lapply(V1:V4,function(i)(a[[i]]*b[,i]))],
mm = b*rep(unlist(a),each=nrow(b)),
mm_cheat = b*rep_a,
regular_sweep = sweep(b,2,unlist(a),`*`),
regular_sweep2 = sweep(b,2,a_vec,`*`),
improved_sweepA1 = b*aperm(array(unlist(a),rev(dim(b)))),
improved_sweepA2 = b*aperm(array(a_vec,rev(dim(b)))),
improved_sweepB1 = b*a[rep_len(1,nrow(b)),],
improved_sweepB2 = b*t(a_vec)[rep_len(1,nrow(b)),],
unit = "relative",
times=50)


Unit: relative
expr min lq mean median uq max neval
mkr1 42.12228 44.15266 50.23959 46.35240 57.20280 65.07289 50
mkr2 114.58427 124.19653 125.25660 131.08677 124.17058 114.91137 50
mkr_update 1.00000 1.00000 1.00000 1.00000 1.00000 1.00000 50
mm 231.34331 223.74365 217.50145 225.91117 215.90765 165.64814 50
mm_cheat 13.38838 13.22556 14.94682 13.36649 12.95260 25.15564 50
regular_sweep 96.15758 124.26746 121.04428 128.67282 129.19407 119.20210 50
regular_sweep2 97.79001 124.69191 124.74650 134.64249 134.97407 107.47152 50
improved_sweepA1 96.57837 124.86189 116.93736 127.08909 124.92805 105.83318 50
improved_sweepA2 96.27737 122.49773 118.45262 128.13369 126.15029 106.58669 50
improved_sweepB1 214.95773 227.39523 226.04339 248.38553 232.50401 161.45341 50
improved_sweepB2 31.20967 32.61873 37.74552 33.70969 41.52149 55.93362 50

关于R - 将 df 或矩阵的每一行与一个向量相乘,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49462591/

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