Python合并两个字典而不丢失顺序

Question

• 我有一个字典，其中包含为如下文档生成的 UUID。

{
  "UUID": [
    "b8f2904b-dafd-4be3-9615-96bac8e16c7f",
    "1240ad39-4815-480f-8cb2-43f802ba8d4e"
  ]
}

• 还有一个嵌套字典

{
  "R_Id": 304,
  "ContextKey": "Mr.Dave",
  "ConsolidationInformation": {
    "Input": [
      {
        "DocumentCode": "BS",
        "ObjectType": "Document",
        "InputContextKey": "Mr.Dave_HDFC.pdf2022-08-010T09:40:06.429358"
      },
      {
        "DocumentCode": "F16",
        "ObjectType": "Document",
        "InputContextKey": "Mr.Dave_F16.pdf2022-08-010T09:40:06.429358"
      }
    ]
  }
}

• 我想通过索引将 UUID 添加到 ['ConsolidationInformation']['Input'] 和内部 Input 作为 DocumentUUID，如何使用 for 循环映射它。我尝试在互联网上搜索，但没有找到可以满足这种嵌套条件的解决方案。
• 预期产出

{
  "R_Id": 304,
  "ContextKey": "Mr.Dave",
  "ConsolidationInformation": {
    "Input": [
      {
        "DocumentCode": "BS",
        "ObjectType": "Document",
        "InputContextKey": "Mr.Dave_HDFC.pdf2022-08-010T09:40:06.429358",
        "DocumentUUID": "b8f2904b-dafd-4be3-9615-96bac8e16c7f"
      },
      {
        "DocumentCode": "F16",
        "ObjectType": "Document",
        "InputContextKey": "Mr.Dave_F16.pdf2022-08-010T09:40:06.429358",
        "DocumentUUID": "1240ad39-4815-480f-8cb2-43f802ba8d4e"
      }
    ]
  }
}

• 我尝试了类似下面的方法，但结果是

Traceback (most recent call last):
File "<string>", line 26, in <module>
KeyError: 0

• 代码

uuid = {
  "UUID": [
    "b8f2904b-dafd-4be3-9615-96bac8e16c7f",
    "1240ad39-4815-480f-8cb2-43f802ba8d4e"
  ]
}
document = {
  "R_Id": 304,
  "ContextKey": "Mr.Dave",
  "ConsolidationInformation": {
    "Input": [
      {
        "DocumentCode": "BS",
        "ObjectType": "Document",
        "InputContextKey": "Mr.Dave_HDFC.pdf2022-08-010T09:40:06.429358"
      },
      {
        "DocumentCode": "F16",
        "ObjectType": "Document",
        "InputContextKey": "Mr.Dave_F16.pdf2022-08-010T09:40:06.429358"
      }
    ]
  }
}
for i, document in enumerate(document):
    uuid = uuid[i]
    print(f"${uuid} for 1 {document}")

Answer 1

问题:您的尝试做得很好。唯一的问题是必须在正确的嵌套级别访问和添加值。

解决方案:您可以按如下方式更正您的尝试:

for i, doc in enumerate(document['ConsolidationInformation']['Input']):
    doc['DocumentUUID'] = uuid['UUID'][i]

或者:您可以使用zip 函数。您可以了解有关此功能的更多信息 here .

下面是一个示例，说明如何将函数应用于您的代码:

for u, doc in zip(uuid['UUID'], document['ConsolidationInformation']['Input']):
    doc['DocumentUUID'] = u

输出:输出如下:

{
   "R_Id":304,
   "ContextKey":"Mr.Dave",
   "ConsolidationInformation":{
      "Input":[
         {
            "DocumentCode":"BS",
            "ObjectType":"Document",
            "InputContextKey":"Mr.Dave_HDFC.pdf2022-08-010T09:40:06.429358",
            "DocumentUUID":"b8f2904b-dafd-4be3-9615-96bac8e16c7f"
         },
         {
            "DocumentCode":"F16",
            "ObjectType":"Document",
            "InputContextKey":"Mr.Dave_F16.pdf2022-08-010T09:40:06.429358",
            "DocumentUUID":"1240ad39-4815-480f-8cb2-43f802ba8d4e"
         }
      ]
   }
}