typescript - item 没有类型注释，在其自己的初始化程序中直接或间接引用

Question

我有一个模型Location，关系是和它自己。

class Location extends Model<Location> {
    ...

    @BelongsTo(() => Location, "countryId")
    public country?: Location;

    @BelongsTo(() => Location, "stateId")
    public state?: Location;

    @HasMany(() => Location, "countryId")
    public states?: Location[];

    @HasMany(() => Location, "stateId")
    public regions?: Location[];

    @HasMany(() => Location, "regionId")
    public places?: Location[];

    ...
}

所以基本上 counties 有很多 states 有很多 region 等等。我想将其实现为 GraphQLType.

我尝试了什么:

const LocationType = new GraphQLObjectType({
    name: "LocationType",
    fields: () => ({
        ...
        states: {type: new GraphQLList(LocationType)},
        ...
    }),
});

我得到的错误

'LocationType' implicitly has type 'any' because it does not have a type annotation and is referenced directly or indirectly in its own initializer.

Answer 1

您只需将 LocationType 类型指定为 GraphQLObjectType。

类似这样的:

const LocationType: GraphQLObjectType = new GraphQLObjectType({
    name: "LocationType",
    fields: () => ({
        ...
        states: {type: new GraphQLList(LocationType)},
        ...
    }),
});