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haskell - 如何使用 Template Haskell 生成导入和样板列表?

转载 作者:行者123 更新时间:2023-12-05 01:15:21 26 4
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我想用代码生成替换这个样板:

import qualified Y15.D01
import qualified Y15.D02
import qualified Y15.D03
import qualified Y15.D04
import qualified Y15.D05
import qualified Y15.D06HM
import qualified Y15.D06IO
import qualified Y15.D06ST
import qualified Y15.D07
import qualified Y15.D08
import qualified Y15.D09
import qualified Y15.D10
import qualified Y15.D11
import qualified Y15.D12
import qualified Y15.D13

...

days :: [(String, [String -> IO String])]
days =
[ ("Y15.D01", i2ios [Y15.D01.solve1, Y15.D01.solve2])
, ("Y15.D02", i2ios [Y15.D02.solve1, Y15.D02.solve2])
, ("Y15.D03", i2ios [Y15.D03.solve1, Y15.D03.solve2])
, ("Y15.D04", i2ios [Y15.D04.solve1, Y15.D04.solve2])
, ("Y15.D05", i2ios [Y15.D05.solve1, Y15.D05.solve2])
, ("Y15.D06HM",i2ios [Y15.D06HM.solve1, Y15.D06HM.solve2]) -- Data.Map.Strict
, ("Y15.D06IO",ioi2ios [Y15.D06IO.solve1, Y15.D06IO.solve2]) -- Data.Array.IO
, ("Y15.D06ST",i2ios [Y15.D06ST.solve1, Y15.D06ST.solve2]) -- Data.Array.ST
, ("Y15.D07", i2ios [Y15.D07.solve1, Y15.D07.solve2])
, ("Y15.D08", i2ios [Y15.D08.solve1, Y15.D08.solve2])
, ("Y15.D09", i2ios [Y15.D09.solve1, Y15.D09.solve2])
, ("Y15.D10", i2ios [Y15.D10.solve1, Y15.D10.solve2])
, ("Y15.D11", s2ios [Y15.D11.solve1, Y15.D11.solve2])
, ("Y15.D12", i2ios [Y15.D12.solve1, Y15.D12.solve2])
, ("Y15.D13", i2ios [Y15.D13.solve1, Y15.D13.solve2])
]
where s2ios :: [a -> b] -> [a -> IO b]
s2ios = fmap (return .)
i2ios :: [a -> Int] -> [a -> IO String]
i2ios = fmap ((return . show) .)
ioi2ios :: [a -> IO Int] -> [a -> IO String]
ioi2ios = fmap (fmap show .)

https://github.com/oshyshko/adventofcode/blob/master/src/Main.hs

我是 Template Haskell 的新手,如果有任何关于从哪里开始的问题的帮助/建议,我将不胜感激:

  1. 如何列出项目中匹配/Y\d\d.D\d\d.*/模式的模块?
  2. 如何为 p.1 生成导入?
  3. 如何从给定模块中检索 solve1solve2 fns 的类型?
  4. 如何生成days列表?

最佳答案

关于问题(2),Haskell 模板无法生成import 语句。您可以在 bug tracker on GitLab 中看到一个非常古老的功能请求。但没有人受到足够的启发来实现它。

关于问题(3),如果模块已经被导入并且它们的名称可以作为字符串使用,您可以像这样使用 TH 来检索每个模块中的绑定(bind)类型。给定:

-- M001.hs
module M001 where
solve1 :: Int
solve1 = 10

-- M002.hs
module M002 where
solve1 :: IO Int
solve1 = return 20

-- THTest1.hs
{-# LANGUAGE TemplateHaskell #-}

module THTest1 where

import M001
import M002

import Language.Haskell.TH

let
modules = ["M001", "M002"]

showType :: String -> Q ()
showType nm = do
Just n <- lookupValueName nm
VarI _ typ _ <- reify n
reportWarning $ show nm ++ " has type " ++ show typ
return ()

in do mapM_ showType (map (++ ".solve1") modules)
return []

然后编译THTest.hs会产生两个警告:

warning: "M001.solve1" has type ConT GHC.Types.Int
warning: "M002.solve1" has type AppT (ConT GHC.Types.IO)
(ConT GHC.Types.Int)

对于问题 (4),这里是一个使用如上定义的模块 M001M002 的简化示例。使用 ghc -ddump-splices 编译此程序以查看为 days 生成的定义:

-- THTest2.hs
{-# LANGUAGE TemplateHaskell #-}

import M001
import M002

import Control.Monad
import GHC.Types
import Language.Haskell.TH

let
-- list of modules to search
modules = ["M001", "M002"]
-- assoc list of adapter function by argument type
funcs = [(ConT ''Int, 'return), (AppT (ConT ''IO) (ConT ''Int), 'id)]

getDay :: String -> Q Exp
getDay modname = do
-- look up name (e.g., M001.solve1)
Just n <- lookupValueName (modname ++ ".solve1")
-- get type of binding
VarI _ typ _ <- reify n
-- look up appropriate adapter function
let Just f = lookup typ funcs
-- ("M001", adapter_f M001.solve1)
[|($(pure $ LitE (StringL modname)),
$(pure $ AppE (VarE f) (VarE n)))|]

makeDays :: Q [Dec]
makeDays = do
[d| days :: [(String, IO Int)]
days = $(ListE <$> mapM getDay modules)
|]
in makeDays

main = do
forM days $ \(modname, action) -> do
putStr modname
putStr ": "
print =<< action

然后运行会输出:

M001: 10
M002: 20

关于haskell - 如何使用 Template Haskell 生成导入和样板列表?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56392332/

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