gpt4 book ai didi

lua - 每个用户的序列号

转载 作者:行者123 更新时间:2023-12-05 01:10:57 24 4
gpt4 key购买 nike

我正在尝试使一个序列号在 Setup Factory 中只使用一次.

思路如下:

当用户输入序列号时,我的安装程序将检查并前进到下一页(如果序列号正确).. 当它“插入序列号”后将用户传递到下一页时,该页面必须有一个按钮称为“立即安装”

当按下按钮 Install Now 时,它将执行查询,方法是先从列表中删除它,然后再安装应用。

The question is : How to delete the serial?

OnNext Action 中的代码:

-- These actions are performed when the Next button is clicked.

-- get the serial number that the user entered
local strSerial = SessionVar.Expand("%SerialNumber%");


-- Trim leading and trailing spaces from the serial number.
strSerial = String.TrimLeft(strSerial);
strSerial = String.TrimRight(strSerial);
SessionVar.Set("%SerialNumber%", strSerial);


-- the name of the serial number list you want to use, e.g. "Serial List 1"
-- (use nil to search through all of the serial number lists)
local strListName = nil;

-- from _SUF70_Global_Functions.lua:
-- search through the specified serial number list for a match
local bSerialIsValid = g_IsSerialNumberInList(strSerial, strListName);

-- if the user entered a valid serial number, proceed to the next screen,
-- otherwise display an error message and check whether they have any retries left
if(bSerialIsValid) then

-- advance to the next screen
Screen.Next();

else

-- user entered an invalid serial number

SerialNumberScreen.AttemptCount = SerialNumberScreen.AttemptCount + 1;

-- display an 'Invalid serial number' message
Dialog.Message(SetupData.GetLocalizedString("MSG_ERROR"), SetupData.GetLocalizedString("ERR_INVALID_SERIAL"));

-- if the user is out of retries, exit the application
if(SerialNumberScreen.AttemptCount >= SerialNumberScreen.MaxAttempts) then
Application.Exit(0);
end

end
  • 在这里您可以生成序列号

enter image description here

我想从此列表中删除序列号。

  • 这是序列号屏幕的 onNext Action 和代码:

enter image description here

最佳答案

您无法编辑已发布设置的项目设置。序列号被加密并嵌入到安装程序中,然后可以对安装程序进行数字签名。无法在运行时编辑该文件。

关于lua - 每个用户的序列号,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45032604/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com