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我想通过 plotly 制作一个类似于以下示例的动画条形图:https://plotly.com/python/animations/
我有以下代码:
fig = px.bar(
eu_vaccine_df.sort_values('date'),
x='country', y='people_vaccinated_per_hundred',
color='country',
animation_frame='date',
animation_group='country',
hover_name='country',
range_y=[0,50],
range_x=[0,30]
)
fig.update_layout(
template='plotly_dark',
margin=dict(r=10, t=25, b=40, l=60)
)
fig.show()
我认为问题与我的数据框的“日期”列有关。目前它是一个日期时间,并已使用 pd.to_datetime(covid_df['date']
我得到的错误如下:
ValueError Traceback (most recent call last)
<ipython-input-185-ff9c8cc72d87> in <module>
7 hover_name='country',
8 range_y=[0,50],
----> 9 range_x=[0,30]
10 )
11 fig.update_layout(
/opt/conda/lib/python3.7/site-packages/plotly/express/_chart_types.py in bar(data_frame, x, y, color, facet_row, facet_col, facet_col_wrap, facet_row_spacing, facet_col_spacing, hover_name, hover_data, custom_data, text, base, error_x, error_x_minus, error_y, error_y_minus, animation_frame, animation_group, category_orders, labels, color_discrete_sequence, color_discrete_map, color_continuous_scale, range_color, color_continuous_midpoint, opacity, orientation, barmode, log_x, log_y, range_x, range_y, title, template, width, height)
352 constructor=go.Bar,
353 trace_patch=dict(textposition="auto"),
--> 354 layout_patch=dict(barmode=barmode),
355 )
356
/opt/conda/lib/python3.7/site-packages/plotly/express/_core.py in make_figure(args, constructor, trace_patch, layout_patch)
2087 if "template" in args and args["template"] is not None:
2088 fig.update_layout(template=args["template"], overwrite=True)
-> 2089 fig.frames = frame_list if len(frames) > 1 else []
2090
2091 fig._px_trendlines = pd.DataFrame(trendline_rows)
/opt/conda/lib/python3.7/site-packages/plotly/basedatatypes.py in __setattr__(self, prop, value)
719 if prop.startswith("_") or hasattr(self, prop):
720 # Let known properties and private properties through
--> 721 super(BaseFigure, self).__setattr__(prop, value)
722 else:
723 # Raise error on unknown public properties
/opt/conda/lib/python3.7/site-packages/plotly/basedatatypes.py in frames(self, new_frames)
2853
2854 # Validate frames
-> 2855 self._frame_objs = self._frames_validator.validate_coerce(new_frames)
2856
2857 # Update
/opt/conda/lib/python3.7/site-packages/_plotly_utils/basevalidators.py in validate_coerce(self, v, skip_invalid)
2540 res.append(self.data_class(v_el))
2541 elif isinstance(v_el, dict):
-> 2542 res.append(self.data_class(v_el, skip_invalid=skip_invalid))
2543 else:
2544 if skip_invalid:
/opt/conda/lib/python3.7/site-packages/plotly/graph_objs/_frame.py in __init__(self, arg, baseframe, data, group, layout, name, traces, **kwargs)
253 _v = name if name is not None else _v
254 if _v is not None:
--> 255 self["name"] = _v
256 _v = arg.pop("traces", None)
257 _v = traces if traces is not None else _v
/opt/conda/lib/python3.7/site-packages/plotly/basedatatypes.py in __setitem__(self, prop, value)
4802 # ### Handle simple property ###
4803 else:
-> 4804 self._set_prop(prop, value)
4805 else:
4806 # Make sure properties dict is initialized
/opt/conda/lib/python3.7/site-packages/plotly/basedatatypes.py in _set_prop(self, prop, val)
5146 return
5147 else:
-> 5148 raise err
5149
5150 # val is None
/opt/conda/lib/python3.7/site-packages/plotly/basedatatypes.py in _set_prop(self, prop, val)
5141
5142 try:
-> 5143 val = validator.validate_coerce(val)
5144 except ValueError as err:
5145 if self._skip_invalid:
/opt/conda/lib/python3.7/site-packages/_plotly_utils/basevalidators.py in validate_coerce(self, v)
1084 v = str(v)
1085 else:
-> 1086 self.raise_invalid_val(v)
1087
1088 if self.no_blank and len(v) == 0:
/opt/conda/lib/python3.7/site-packages/_plotly_utils/basevalidators.py in raise_invalid_val(self, v, inds)
285 typ=type_str(v),
286 v=repr(v),
--> 287 valid_clr_desc=self.description(),
288 )
289 )
ValueError:
Invalid value of type 'pandas._libs.tslibs.timestamps.Timestamp' received for the 'name' property of frame
Received value: Timestamp('2020-12-13 00:00:00')
The 'name' property is a string and must be specified as:
- A string
- A number that will be converted to a string
最佳答案
您应该检查您的“日期”列的类型(更多信息在本文底部)。例如,以下代码作为一个整体工作。
import plotly.express as px
import pandas as pd
url = 'https://raw.githubusercontent.com/owid/covid-19-data/master/public/data/vaccinations/vaccinations.csv'
df = pd.read_csv(url)
country = 'location'
fig = px.bar(
df.sort_values('date'),
x=country, y='people_vaccinated_per_hundred',
color=country,
animation_frame='date',
animation_group=country,
hover_name=country,
range_y=[0,50],
range_x=[0,30]
)
fig.update_layout(
template='plotly_dark',
margin=dict(r=10, t=25, b=40, l=60)
)
fig.show()
不过,我假设您的数据集的“日期”列不是字符串。要检查它是字符串还是其他类型(对于上述数据集,此行已经计算为 str
):
type(df['date'][0])
要创建将日期转换为字符串的列,请将此行放在 fig
赋值行之前:
df['date_str'] = df['date'].apply(lambda x: str(x))
然后,在无花果分配行中,需要将动画帧设置为新列的名称(例如 animation_frame='date_str'
)。
关于不接受日期时间的 plotly (px) animation_frame 错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/66789515/
我想通过 plotly 制作一个类似于以下示例的动画条形图:https://plotly.com/python/animations/ 我有以下代码: fig = px.bar( eu_vacci
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