F# - 如何使用完全相同的命名参数调用 C# 覆盖的方法

Question

如何使用完全相同的命名参数调用 C# 覆盖的方法？

例子

public static Task<CreateImageSummaryModel> CreateImagesFromDataAsync(this ITrainingApi operations, Guid projectId, IEnumerable<Stream> imageData, IList<Guid> tagIds = null, CancellationToken cancellationToken = default(CancellationToken));



public static Task<CreateImageSummaryModel> CreateImagesFromDataAsync(this ITrainingApi operations, Guid projectId, Stream imageData, IList<string> tagIds = null, CancellationToken cancellationToken = default(CancellationToken));

相同的方法名称和参数名称，但参数具有不同的签名。

现在尝试调用第一个方法

let uploadStreams (tag: string) (streams: Stream seq) (projectId: Guid) (trainingApi: TrainingApi) = 

    let tag = trainingApi.CreateTag(projectId, tag)

    let tags = new List<_>([tag.Id])

    let streams = streams :> IEnumerable<Stream>

    trainingApi.CreateImagesFromDataAsync(projectId, imageData = streams, tagIds = tags)

这会产生编译错误

Severity    Code    Description Project File    Line    Suppression State
Error   FS0001  The type 'IEnumerable<Stream>' is not compatible with the type 'Stream' 

Severity    Code    Description Project File    Line    Suppression State
Error   FS0193  Type constraint mismatch. The type     'IEnumerable<Stream>'    is not compatible with type    'Stream' 

Severity    Code    Description Project File    Line    Suppression State
Error   FS0001  The type 'List<Guid>' is not compatible with the type 'IList<string>'   VisionAPI   

通常当我在 F# 中处理重写方法时，我只使用显式参数名称，例如

let x = cls.someOverriddenMethod(arg1 = 1)

但在这种情况下这是行不通的。

在这种情况下我应该如何处理？

谢谢

Answer 1

我认为问题在于 imageData 不是可选参数，但您将其作为一个参数进行传递。只需直接传递 streams 而不是使用 imageData = streams。这是为我编译的最小工作示例:

open System
open System.IO

type MyType () =
    static member A(a: string, b: Guid, c: Stream seq, ?d: Guid list) = ()
    static member A(a: string, b: Guid, c: Stream, ?d: Guid list) = ()

let f (streams: Stream seq) guids =
    MyType.A("", Guid.Empty, streams, d = guids)
    MyType.A("", Guid.Empty, streams |> Seq.head, d = guids)