python - 谷歌python速成类(class)的一个问题

Question

group_list 函数接受组名和成员列表，并返回格式为:group_name: member1, member2, ... 例如 group_list("g", ["a","b","c"]) 返回 "g: a, b, c"。填补这个功能的空白来做到这一点。

def group_list(group, users):
  members = ___
  return ___

print(group_list("Marketing", ["Mike", "Karen", "Jake", "Tasha"])) # Should be "Marketing: Mike, Karen, Jake, Tasha"
print(group_list("Engineering", ["Kim", "Jay", "Tom"])) # Should be "Engineering: Kim, Jay, Tom"
print(group_list("Users", "")) # Should be "Users:"

我试过这样的:

members = " " 
for i in users:
    members += ",".join(i)
return ("{}:{}".format(group, members))

输出来了:

Marketing: M,i,k,eK,a,r,e,nJ,a,k,eT,a,s,h,a
Engineering: K,i,mJ,a,yT,o,m
Users: 

但它没有给出预期的答案。请问谁能解决这个问题？

Answer 1

您需要加入用户，而不是单独加入每个用户。

members = ', '.join(users)
return "{}: {}".format(group, members)