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r - 两个 sf 对象的空间合并

转载 作者:行者123 更新时间:2023-12-05 00:46:34 26 4
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我正在尝试合并两个数据框(主数据框和子数据框)。我希望“子”中的“变量”数据根据距离或更好的距离合并到“主”,无论哪个“子”行/站点最接近“主”行/站点。

library(sf)

a <- structure(list(`Site#` = c("Site1", "Site2", "Site3", "Site4", "Site5", "Site6"), Longitude = c(-94.609, -98.1391, -99.033, -98.49, -96.4309, -95.99), `Latitude` = c(38.922, 37.486111, 37.811, 38.364, 39.4402, 39.901)), row.names = c(NA, -6L), class = c("tbl_df", "tbl", "data.frame"))

main <- st_as_sf(a, coords = c("Longitude", "Latitude"), crs = 4326)

b <- structure(list(Longitude = c(-98.49567, -96.22451, -98.49567, -98.941391, -95.91411, -99.031113), `Latitude` = c(38.31264,39.97692, 38.31264, 37.486111, 39.92143, 37.814171), Variable = c(400, 50, 100, 201, 99, 700)), row.names = c(NA, -6L), class = c("tbl_df", "tbl", "data.frame"))

sub <- st_as_sf(b, coords = c("Longitude", "Latitude"), crs = 4326)

c <- st_intersection(main,sub)
c <- st_is_within_distance(main,sub,dist=0.001)

我相信 st_intersection 是我想要的,但如果我可以根据距离一对一地做到这一点,那就可以了。有谁知道什么可以提供我正在寻找的结果?

最佳答案

st_join() 允许一步加入:

st_join(main, sub, join = st_nearest_feature, left = T)


#> although coordinates are longitude/latitude, st_nearest_feature assumes that they are planar
#> Simple feature collection with 6 features and 2 fields
#> geometry type: POINT
#> dimension: XY
#> bbox: xmin: -99.033 ymin: 37.48611 xmax: -94.609 ymax: 39.901
#> epsg (SRID): 4326
#> proj4string: +proj=longlat +datum=WGS84 +no_defs
#> # A tibble: 6 x 3
#> `Site#` geometry Variable
#> <chr> <POINT [°]> <dbl>
#> 1 Site1 (-94.609 38.922) 99
#> 2 Site2 (-98.1391 37.48611) 201
#> 3 Site3 (-99.033 37.811) 700
#> 4 Site4 (-98.49 38.364) 400
#> 5 Site5 (-96.4309 39.4402) 50
#> 6 Site6 (-95.99 39.901) 99

reprex package 于 2020-01-19 创建(v0.3.0)

关于r - 两个 sf 对象的空间合并,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59815397/

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