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R Plotly在循环内添加跟踪

转载 作者:行者123 更新时间:2023-12-05 00:39:52 25 4
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我在使用循环在 plotly 中添加跟踪时遇到问题,但我不知道原因是什么。

如果我尝试使用下面的 P 方法绘制图,则仅显示最后一列 (HORSE) 的数据。 Rabbit 和 Dog 仍然显示,但都显示 Horse 的值。

但是,如果我使用 P1 方法,则该图可以完美运行。我真的希望能够在一个循环中执行此操作,因为列的长度会有所不同。

 df <- data.frame(AGE    = c(0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,2,2,2,2,2,2,2,2,3,3,3,3,3,3,3,3,4,4,4,4,4,4,4,4,5,5,5,5,5,5,5,5),
YEAR = c(2010,2011,2012,2013,2014,2015,2016,2017,2010,2011,2012,2013,2014,2015,2016,2017,2010,2011,2012,2013,2014,2015,2016,2017,2010,2011,2012,2013,2014,2015,2016,2017,2010,2011,2012,2013,2014,2015,2016,2017,2010,2011,2012,2013,2014,2015,2016,2017),
RABBIT = c(0,5,2,6,8,5,8,4,3,6,2,7,5,5,9,9,1,4,4,6,5,3,7,7,6,8,2,6,9,1,9,1,1,2,10,1,10,10,4,2,4,8,7,0,3,4,5,7),
DOG = c(2,5,0,8,2,5,9,5,10,5,10,3,8,9,2,7,5,1,1,4,6,7,7,0,6,5,7,2,2,9,4,2,6,0,7,1,7,6,9,9,9,5,5,9,0,9,10,2),
HORSE = c(7,1,9,10,6,6,5,1,4,5,0,3,0,3,2,4,3,6,1,9,6,4,3,1,7,8,4,1,8,6,5,9,2,0,5,5,6,1,1,7,4,9,5,0,8,1,5,7)
)

L <- c("RABBIT","DOG","HORSE")

P <- plot_ly(data = df)
for(i in 1:length(L)){
P<-add_trace(P, y=~df[[L[i]]], x=~df$AGE, frame =~df$YEAR, type="scatter", mode="lines", name = L[i])
}

P1 <- plot_ly(data = df)
P1 <- add_trace(P1, y=~df[[L[1]]], x=~df$AGE, frame =~df$YEAR, type="scatter", mode="lines", name = L[1])
P1 <- add_trace(P1, y=~df[[L[2]]], x=~df$AGE, frame =~df$YEAR, type="scatter", mode="lines", name = L[2])
P1 <- add_trace(P1, y=~df[[L[3]]], x=~df$AGE, frame =~df$YEAR, type="scatter", mode="lines", name = L[3])

P enter image description hereP1 enter image description here

最佳答案

你可以使用这个解决方案:

P <- plot_ly(data = df)
for(k in 1:length(L)) {
dfk <- data.frame(y=df[[L[k]]], AGE=df$AGE, YEAR=df$YEAR)
P <- add_trace(P, y=~y, x=~AGE, frame =~YEAR, data=dfk,
type="scatter", mode="lines", name = L[k])
}

关于R Plotly在循环内添加跟踪,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54788327/

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