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haskell - 无限精度整数 : division by 2

转载 作者:行者123 更新时间:2023-12-05 00:28:55 27 4
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在 C 中,如果我想将 int 除以 2,x%2应该像 (x%10)% 2 一样快
因为一个好的编译器只会看最后一点。但是在具有无限精度算术的语言中呢?

特别是,在 Haskell 中会更快(或者它们的速度相同):even xeven (quot x 10) ?

最佳答案

好吧,我咬一口:

import Control.DeepSeq
import Criterion.Main
import Data.Bits
import System.Random

lotsOfBigNumbers :: [Integer]
lotsOfBigNumbers = take 10000 $ randomRs (2^128, 2^132) (mkStdGen 42)

evenRem, evenBits :: Integer -> Bool
evenRem x = even (x `rem` 10)
evenBits x = (x .&. 1) == 0
remRem x = ((x `rem` 10) `rem` 2) == 0

main = do
deepseq lotsOfBigNumbers (return ())
defaultMain
[ bench "even" $ nf (map even ) lotsOfBigNumbers
, bench "evenRem" $ nf (map evenRem ) lotsOfBigNumbers
, bench "evenBits" $ nf (map evenBits) lotsOfBigNumbers
, bench "remRem" $ nf (map remRem ) lotsOfBigNumbers
]

结果:
sorghum:~/programming% ghc -O2 test && ./test
[1 of 1] Compiling Main ( test.hs, test.o )
Linking test ...
warming up
estimating clock resolution...
mean is 1.920340 us (320001 iterations)
found 51108 outliers among 319999 samples (16.0%)
46741 (14.6%) low severe
4367 (1.4%) high severe
estimating cost of a clock call...
mean is 83.20445 ns (16 iterations)
found 4 outliers among 16 samples (25.0%)
2 (12.5%) low mild
2 (12.5%) high severe

benchmarking even
mean: 1.508542 ms, lb 1.503661 ms, ub 1.514950 ms, ci 0.950
std dev: 28.53574 us, lb 23.35796 us, ub 35.19769 us, ci 0.950
found 18 outliers among 100 samples (18.0%)
17 (17.0%) high severe
variance introduced by outliers: 11.371%
variance is moderately inflated by outliers

benchmarking evenRem
mean: 1.937735 ms, lb 1.930118 ms, ub 1.949699 ms, ci 0.950
std dev: 48.17240 us, lb 34.95334 us, ub 71.22055 us, ci 0.950
found 14 outliers among 100 samples (14.0%)
3 (3.0%) high mild
11 (11.0%) high severe
variance introduced by outliers: 18.989%
variance is moderately inflated by outliers

benchmarking evenBits
mean: 996.3537 us, lb 992.2839 us, ub 1.003864 ms, ci 0.950
std dev: 27.37875 us, lb 17.51923 us, ub 43.98499 us, ci 0.950
found 15 outliers among 100 samples (15.0%)
2 (2.0%) high mild
13 (13.0%) high severe
variance introduced by outliers: 21.905%
variance is moderately inflated by outliers

benchmarking remRem
mean: 1.925495 ms, lb 1.918590 ms, ub 1.935869 ms, ci 0.950
std dev: 43.00092 us, lb 31.67173 us, ub 57.83841 us, ci 0.950
found 13 outliers among 100 samples (13.0%)
13 (13.0%) high severe
variance introduced by outliers: 15.198%
variance is moderately inflated by outliers

结论:一个额外的 rem成本稍高,而且 .&.花费少一点。

关于haskell - 无限精度整数 : division by 2,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18043271/

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