android - new AsyncHttpResponseHandler() 总是会失败

Question

AsyncHttpClient client = new AsyncHttpClient();
RequestParams params = new RequestParams();    
params.put("username", username);
params.put("password", password);
client.post("192.168.12.4/administration/include/login.php", params, new AsyncHttpResponseHandler() {
        @Override
        public void onSuccess(String response) {
            System.out.println("onSuccess");
            Toast.makeText(getApplicationContext(), "MySQL DB has been informed about Sync activity", Toast.LENGTH_LONG).show();
        }

        @Override
        public void onFailure(int statusCode, Throwable error, String content) {
            System.out.println("onFailure");
            Toast.makeText(getApplicationContext(), "Error Occured", Toast.LENGTH_LONG).show();
        }
    });

如果我有上面的代码可能会导致它转到 public void onFailure(int statusCode, Throwable error, String content) {}而不是 public void onSuccess(String response) {}
在哪里 192.168.12.4是运行 localhost 的计算机的 IP，以及包含 login.php 的项目所在的计算机的 IP。位于

Answer 1

如果这是用于模拟器测试的开发人员计算机(运行模拟器的 PC)，则必须将 URL 值更改为

http://10.0.2.2/administration/include/login.php

并且不要忘记将其添加到您的 list 文件中

<uses-permission android:name="android.permission.INTERNET" />