android - 如何在 Firebase 中创建用户时获取用户 ID

Question

在我的项目中，只有管理员可以将用户添加到 firebase。
在创建时我想获取用户 ID，因为我想在 Firebase 数据库中设置该用户的配置文件。

public void addNewFaculty(View view){
    String name,email,password,rePassword;
    name = txtname.getText().toString();
    email = txtEmail.getText().toString().trim();
    password = txtPassword.getText().toString().trim();
    rePassword = txtRepassword.getText().toString().trim();
    if(password.equals(rePassword))
    {
        Toast.makeText(this, "Password is not match", Toast.LENGTH_SHORT).show();
        return;
    }
    databaseReference= FirebaseDatabase.getInstance().getReference();
    firebaseUser = firebaseAuth.getCurrentUser();
    String id= firebaseUser.getUid();
    databaseReference = databaseReference.child("Profile").child(id);
    databaseReference.child("Name").setValue(name);
    // and some other things
    firebaseAuth.createUserWithEmailAndPassword(email,password)
            .addOnCompleteListener(this, new OnCompleteListener<AuthResult>() {
                @Override
                public void onComplete(@NonNull Task<AuthResult> task) {
                    if(task.isSuccessful()){
                        Toast.makeText(getApplicationContext(), "Employee Added Successfully", Toast.LENGTH_SHORT).show();
                    }else{
                        Toast.makeText(getApplicationContext(), "Please try Again", Toast.LENGTH_SHORT).show();
                    }
                }
            });

}

我的火力基地结构是
我的firebase结构如下。我想在创建用户时获取用户 ID
Here is my Firebase Auth Image

And want to set id here

Answer 1

当您在 firebase auth 中创建用户时，它会自动登录。因此您可以在 onComplete() 中获取您的 id，如果方法如下:

    if(task.isSuccessful()){
       String id1 = firebaseAuth.getCurrentUser().getUid();
       //For adding into database

       databaseReference = databaseReference.child("Profile").child(id1);
       databaseReference.child("Name").setValue(name);

       Toast.makeText(getApplicationContext(), "Employee Added Successfully", Toast.LENGTH_SHORT).show();
    }else{
       Toast.makeText(getApplicationContext(), "Please try Again", Toast.LENGTH_SHORT).show();
    }