Django-rest-framework 创建具有多对多关系的对象

Question

我需要创建对象“标签”，其中多对多关系附加到对象“任务”。我有这段代码，但不明白为什么它不起作用。我看到错误无法将关键字“任务”解析为字段。选项有:id、名称、标签、
附言
我靠这个帖子manyToMany with django rest framework

。楷模

class Tag(models.Model):
    name = models.CharField(max_length=200)
    def __str__(self):
        return "{}".format(self.name)

class Task(models.Model):
    name = models.CharField(max_length=200, blank=True)
    tags = models.ManyToManyField(Tag)
    def __str__(self):
        return "{}".format(self.name)

.views

class TagCreateView(generics.ListCreateAPIView):
    serializer_class = TagSerializer

    def get_queryset(self):
        queryset = Tag.objects.all()
        task_id = self.kwargs.get('task_id', None)
        if task_id is not None:
            queryset = queryset.filter(task=task_id)
        return queryset
    def perform_create(self, serializer):
        task_id = self.kwargs.get('task_id', None)
        try:
            tasks = Task.objects.get(task__id__exact=task_id)
        except Task.DoesNotExist:
            raise NotFound()
        serializer.save(tag=tasks)

.serelizers

class TagSerializer(serializers.ModelSerializer):
    class Meta:
        model = Tag
        fields = ('id', 'name','')

class TaskSerializer(serializers.ModelSerializer):
    tag = TagSerializer(many=True, read_only=True)
    class Meta:
        model = Task
        fields = ('id', 'name', 'tags')
        read_only_fields = ('tags')

.urls

urlpatterns = {
url(r'^todolists/(?P<task_id>[0-9]+)/tags', TagCreateView.as_view(), name="tags")}

Answer 1

您需要在序列化程序中处理嵌套序列化程序的创建 create方法;

如下所示:http://www.django-rest-framework.org/api-guide/serializers/#writing-create-methods-for-nested-representations