sql - 如何构建一个将行选择为 SQL 列的查询？

Question

如何在 SQL Server 中编写一个查询，为每个唯一 ID 的每个变量返回一列？下面是我想要完成的任务的简化示例。你能指出我正确的方向吗？

Table_Exists

ID    |    LOCATION    |    STATUS
__________________________________
001   |     top        |     3
001   |     mid        |     1
001   |     bot        |     4
002   |     top        |     2
002   |     mid        |     2
002   |     bot        |     1
003   |     top        |     1
003   |     mid        |     4
003   |     bot        |     2

这是我正在尝试的简化示例，显然没有成功。下面的代码会因“=”周围的语法不正确而返回错误消息:

SELECT  
  ID,
  LOCATION = top AS Top,
  LOCATION = mid AS Middle,
  LOCATION = bot AS Bottom
FROM 
  Table_Exists

我试图构建:

Table_Desired

ID | Top | Middle | Bottom 
__________________________
001|  3  |   1    |  4
002|  4  |   2    |  2 
003|  1  |   4    |  2

Answer 1

您可以使用自连接(只要您的 LOCATION 为 NOT NULL 并且它包含所有 top/mid/bot 值):

 SELECT t1.ID, t1.Status AS Top, t2.Status AS Middle, t3.Status AS Bottom
 FROM Table_Exists t1
 JOIN Table_Exists t2
   ON t1.ID = t2.ID
  AND t1.LOCATION = 'top'
  AND t2.Location = 'mid'
 JOIN Table_Exists t3
   ON t1.ID = t3.ID
  AND t1.LOCATION = 'top'
  AND t3.Location = 'bot';

LiveDemo

要获得更通用的解决方案，请使用PIVOT:

SELECT
     [ID]
    ,[Top]    = [top] 
    ,[Middle] = [mid]
    ,[Bottom] = [bot]
FROM #Table_Exists t
PIVOT (
   MAX(STATUS) FOR LOCATION IN ([top],[mid],[bot])
) AS Piv

LiveDemo2