android - 单击通知后调用服务中的方法

Question

我有一个通知，我正在从服务中调用它。我想在单击通知时再次调用该服务。但是通知点击无法进入方法内部。

Intent intent = new Intent(this, MyService.class).setAction(ACTION_1);
PendingIntent resultPendingIntent = PendingIntent.getActivity(this, 0,intent, PendingIntent.FLAG_UPDATE_CURRENT | PendingIntent.FLAG_ONE_SHOT);

    NotificationCompat.Builder mBuilder =
            new NotificationCompat.Builder(this)
                    .setSmallIcon(R.drawable.food)
                    .setContentTitle("notification")
                    .setContentText("near by you!");
   NotificationManager mNotificationManager =(NotificationManager) getSystemService(Service.NOTIFICATION_SERVICE);

我想调用的方法是

if (ACTION_1.equals(resultPendingIntent)) {
        getRecommendation();
    } 
        mBuilder.setContentIntent(resultPendingIntent);
    mNotificationManager.notify(id, mBuilder.build());

我尝试了以下链接，但无法解决我的问题。
How to execute a method by clicking a notification

Answer 1

您可以指定 Broadcast在您的 Service并通过 PendingIntent 启动它在您的通知中。

Intent stopIntent = new Intent("my.awersome.string.name");
PendingIntent stopPi = PendingIntent.getBroadcast(this, 4, stopIntent, PendingIntent.FLAG_CANCEL_CURRENT);

然后，在您的通知生成器中:

NotificationCompat.Builder builder;
builder = new NotificationCompat.Builder(context)
    ...     
    .setContentIntent(stopPi);

在您的 Service你可以设置一个 BroadcastReceiver作为:

private final BroadcastReceiver myReceiver = new BroadcastReceiver() {
    @Override
    public void onReceive(Context context, Intent intent) {
        // Code to run
    }
};

您注册 receiver在您的 Service (可能在 onStartCommand() 中)仅使用:

registerReceiver(myReceiver, new IntentFilter("my.awersome.string.name"));

您的 Service必须运行才能使其正常工作。