android - Http 请求在 Flutter 中不返回任何内容，也不会抛出任何错误

Question

使用简单的默认 http 库，这真的让我很困惑。 Http 请求永远不会返回，也不会抛出任何错误。

医生日志如下:

[√] Flutter (Channel master, 1.19.0-2.0.pre.34, on Microsoft Windows [Version 10.0.18362.836], locale en-US)
    • Flutter version 1.19.0-2.0.pre.34 at E:\FlutterSDK
    • Framework revision 610dc170d9 (3 days ago), 2020-05-14 00:37:02 +0800
    • Engine revision b59e3e9c39
    • Dart version 2.9.0 (build 2.9.0-8.0.dev 2bf3259005)


[√] Android toolchain - develop for Android devices (Android SDK version 29.0.2)
    • Android SDK at E:\AndroidSDK
    • Platform android-29, build-tools 29.0.2
    • ANDROID_HOME = E:\AndroidSDK
    • Java binary at: E:\android-studio\jre\bin\java
    • Java version OpenJDK Runtime Environment (build 1.8.0_202-release-1483-b03)
    • All Android licenses accepted.

[√] Android Studio (version 3.5)
    • Android Studio at E:\android-studio
    • Flutter plugin version 42.1.1
    • Dart plugin version 191.8593
    • Java version OpenJDK Runtime Environment (build 1.8.0_202-release-1483-b03)

[√] Connected device (1 available)
    • Android SDK built for x86 • emulator-5554 • android-x86 • Android 9 (API 28) (emulator)

这是代码:

clockIn(String number, String name, String company, String coords) async {
  print(uri);

  // var response = await http.post(uri, body: {
  //   'Employee_Number': number,
  //   'Employee_Name': name,
  //   'Company_Name': company,
  //   'Coords_In': coords,
  //   'Type': 'IN'
  // });

  var response = await http.get("https://google.com");

  final statusCode = response.statusCode;
  print('Response Status code: $statusCode');
}

我也尝试过 try-catch ，但没有任何返回。任何地方也没有任何错误。真的让我很困惑。我在 AVD 以及我自己的设备上进行了尝试。

这里是它的名字:

onPressed: () {
                      if (!isActivated) return;
                      getEmployeeData().then((value) async {
                        Position pos = await Geolocator().getCurrentPosition(
                            desiredAccuracy: LocationAccuracy.best);

                        clockIn(value[0], value[1], value[2],
                            "${pos.latitude}, ${pos.longitude}");
                      });
                    }

Answer 1

我认为这是因为谷歌，我尝试了不同网址的代码，例如它得到了响应；

clockIn() async {
    print("uri");
    var myUrl = 'https://www.msn.com';
    var response = await http.get(myUrl);
    print('Response status: ${response.statusCode}');
    print('Response body: ${response.body}');
  }