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verilog - 实现处理器(mips单周期)

转载 作者:行者123 更新时间:2023-12-05 00:03:58 24 4
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我有一个迷你项目,在这个项目中我需要通过 Verilog 实现一个 MIPS 单周期处理器。
在这里,我编写了 ALU 和 ALUControl 和 FileRegister,但是我在为此实现 Pc(程序计数器)时遇到了问题……我想要这个 Pc 支持分支和跳转。
我需要支持分支的说明,但我不知道如何访问说明。
请帮我实现 InstructionMemory 和 Pc。
这是我的代码:

module ALU(ALUctl, A, B, ALUOut, Zero);
input [3:0] ALUctl;
input [31:0] A,B;
output reg [31:0] ALUOut;
output Zero;
assign Zero = (ALUOut==0); //Zero is true if ALUOut is 0
always @(ALUctl, A, B) begin //reevaluate if these change
case (ALUctl)
0: ALUOut <= A & B;
1: ALUOut <= A | B;
2: ALUOut <= A + B;
6: ALUOut <= A - B;
7: ALUOut <= A < B ? 1 : 0;
12: ALUOut <= ~(A | B); // result is nor
default: ALUOut <= 0;
endcase
end

端模块
module ALUControl(ALUOp, FuncCode, ALUCtl);
input [1:0] ALUOp;
input [5:0] FuncCode;
output reg [3:0] ALUCtl;
always @(ALUOp, FuncCode) begin
if ( ALUOp == 2 )
case (FuncCode)
32: ALUCtl<=2; // add
34: ALUCtl<=6; //subtract
36: ALUCtl<=0; // and
37: ALUCtl<=1; // or
39: ALUCtl<=12; // nor
42: ALUCtl<=7; // slt
default: ALUCtl<=15; // should not happen
endcase
else
case (ALUOp)
0: ALUCtl<=2;
1: ALUCtl<=6;
default: ALUCtl<=15; // should not happen
endcase
end

端模块
module RegFile(ra1, rd1 , ra2 , rd2 , clk , RegWrite , wa ,wd );
input[4:0] ra1;
output[31:0] rd1;
input[4:0] ra2;
output[31:0] rd2;
input clk;
input werf ;
input[4:0] wa;
input[31:0] wd;
reg [31:0] registers[31:0];

assign rd1 = registers[ra1];
assign rd2 = registers[ra2];

always@ ( posedge clk )
if (RegWrite)
registers[wa] <= wd;

端模块

最佳答案

这是电脑的代码

module PC(clk  , instruction ,  zero , branch , jump , pc );
input clk ;
input[31:0] instruction ;
reg[31:0] npc;
input zero ;
input jump ;
input branch ;
wire[31:0] pcInc;
wire[31:0] Branch1 ;
wire[15:0] address;
wire[31:0] branchAdd;
reg[31:0] mux1;
wire select1 ;
wire[31:0] jumpAdd ;
output [31:0] pc ;
reg [31:0] pc ;


assign select1 = branch & zero ;
assign pcInc = pc + 4 ;
assign address = instruction[15:0];
assign Branch1 = {{16{address[15]}},address[15:0]} ; // sign extension
assign branchAdd = pcInc + ( branch << 2 ) ;

always@( branchAdd or pcInc or select1 )
begin
if ( select1 == 1 )
mux1 = branchAdd ;
else
mux1 = pcInc ;
end

assign jumpAdd = ( instruction[25:0] << 2 );

always@ ( jump or jumpAdd or mux1 )
begin
if ( jump == 1 )
npc = jumpAdd ;
else
npc = mux1;
end

always @(posedge clk )
pc <= npc;

端模块

关于verilog - 实现处理器(mips单周期),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6197733/

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