sql - Oracle SQL 查询 : how to use count

Question

我有以下格式的数据

userid  amount  term  APR
1        10       5    1
1        10       4    2
2        20       6    1
2        20       4    3
2        20       3    1

我想按金额、期限、APR 排序，所以在输出中我想要最大金额，它是相应的期限，APR。如果金额相同，请选择具有最大期限的一项，如果期限也相同，则情况相同。但是这三者的结合总是独一无二的。

输出列:

userid,  amount, term, apr, numberOfRowsForEachUser
  1       10       5   1      2
  2       20       6   1      3

问题:我能够获得前四列，但不确定如何获得“报价总数”或“每位用户的总行数”。

我的查询看起来像这样。

select 
  userid,amount,term,apr
  from 
( select userid, amount, term,  apr
   RANK() OVER (PARTITION BY userid ORDER BY amount,term,apr) amount_rank,   
from 
   tableXYZ
) 
where amount_rank = 1 

Answer 1

只需添加一个 COUNT(*)解析函数

select 
  userid,amount,term,apr, cnt
  from 
( select userid, amount, term,  apr
   RANK() OVER (PARTITION BY userid ORDER BY amount,term,apr) amount_rank,   
   COUNT(*) OVER (PARTITION BY userid) cnt
from 
   tableXYZ
) 
where amount_rank = 1