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wpf - WPF 中的 Google 样式按钮

转载 作者:行者123 更新时间:2023-12-04 23:53:13 26 4
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我正在尝试为我的应用程序制作自定义按钮,但进展并不顺利。

我有以下 XAML 仅用于测试目的:

<Style x:Key="DefBtn" TargetType="{x:Type Button}">
<Setter Property="FocusVisualStyle" Value="{StaticResource ButtonFocusVisual}"/>
<Setter Property="Background" Value="{StaticResource ButtonNormalBackground}"/>
<Setter Property="BorderBrush" Value="{StaticResource ButtonNormalBorder}"/>
<Setter Property="BorderThickness" Value="1"/>
<Setter Property="Foreground" Value="{DynamicResource {x:Static SystemColors.ControlTextBrushKey}}"/>
<Setter Property="HorizontalContentAlignment" Value="Center"/>
<Setter Property="VerticalContentAlignment" Value="Center"/>
<Setter Property="Padding" Value="1"/>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<Border Name="border"
BorderThickness="1"
Padding="4,2"
BorderBrush="DarkGray"
CornerRadius="3"
Background="{TemplateBinding Background}">
<Grid >
<ContentPresenter HorizontalAlignment="Center"
VerticalAlignment="Center" Name="content"/>
</Grid>
</Border>

<ControlTemplate.Triggers>
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="border" Property="BorderBrush" Value="Yellow" />
<Setter Property="Foreground" Value="#FF4788c8" />
</Trigger>
<Trigger Property="IsEnabled" Value="false">
<Setter Property="Foreground" Value="#ADADAD"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>

-

<Button x:Name="btnCancelTimer" Content="{Binding [LangResources.timerDetail4], FallbackValue=Cancel Timer, Mode=OneWay, Source={StaticResource localisation}}" Margin="231,0,231,32.04" VerticalAlignment="Bottom" IsCancel="True" FontSize="13.333" Click="BtnCancelTimerClick" Cursor="Hand" Foreground="#FF666666" Background="White" FontFamily="Arial" FontWeight="Bold" Width="115" Height="24" Style="{DynamicResource DefBtn}" />

我正在尝试实现与此完全相同的按钮样式,还包括按钮上的鼠标悬停和按下样式。

Google Button

任何人都可以帮助/指导我如何实现这一目标吗?

谢谢

最佳答案

尝试使用这种风格

<Style x:Key="DefBtn" TargetType="{x:Type Button}">
<Setter Property="Background" Value="#FFF5F5F5"/>
<Setter Property="BorderBrush" Value="#FFDCDCDC"/>
<Setter Property="BorderThickness" Value="1"/>
<Setter Property="Foreground" Value="#FF666666"/>
<Setter Property="FontWeight" Value="Bold"/>
<Setter Property="FontSize" Value="11"/>
<Setter Property="FontFamily" Value="Arial"/>
<Setter Property="HorizontalContentAlignment" Value="Center"/>
<Setter Property="VerticalContentAlignment" Value="Center"/>
<Setter Property="Padding" Value="8,7"/>
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="Button">
<Border Name="border"
BorderThickness="{TemplateBinding BorderThickness}"
Padding="{TemplateBinding Padding}"
BorderBrush="{TemplateBinding BorderBrush}"
CornerRadius="1"
Background="{TemplateBinding Background}">
<ContentPresenter HorizontalAlignment="{TemplateBinding HorizontalContentAlignment}"
VerticalAlignment="{TemplateBinding VerticalContentAlignment}"/>
</Border>
<ControlTemplate.Triggers>
<!--TODO: Set the right colors-->
<Trigger Property="IsMouseOver" Value="True">
<Setter TargetName="border" Property="BorderBrush" Value="Yellow" />
<Setter Property="Foreground" Value="#FF4788c8" />
</Trigger>
<Trigger Property="IsPressed" Value="True">
<!--Some setters here-->
</Trigger>
<Trigger Property="IsEnabled" Value="false">
<Setter Property="Foreground" Value="#ADADAD"/>
</Trigger>
</ControlTemplate.Triggers>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>

我对字体不太感兴趣,但 Arial 似乎非常接近。 KaXaml 显示这种风格如下:

Google button style

此外,您还需要检查 MouseOver、Pressed 和 Disabled (IsEnabled=false) 触发器\状态的 setter 。

关于wpf - WPF 中的 Google 样式按钮,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6889213/

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