gpt4 book ai didi

java - Android FFmpegMediaMetadataRetriever.getFrameAtTime() 很慢

转载 作者:行者123 更新时间:2023-12-04 23:51:28 25 4
gpt4 key购买 nike

我正在开发一个应用程序,该应用程序最终将以 200 毫秒的间隔将视频切割成帧。

该应用程序可以工作,您选择一个视频,该应用程序会将其切割成存储在设备上的位图。问题是,FFmpegMediaMetaRetriever.getFrameAtTime() 非常慢。我的意思是,处理视频所需的时间比视频长度本身要长,我看到平均每帧大约 1.1 秒。

我已经跟踪到调用 getFrameAtTime 的延迟。还有其他人知道在特定时间从视频中获取帧的更好方法吗?

代码:

    new Thread(new Runnable() {
@Override
public void run() {
FFmpegMediaMetadataRetriever retriever = new FFmpegMediaMetadataRetriever();
retriever.setDataSource(getPath(EditVideo.this, mMediaUri));
String time = retriever.extractMetadata(FFmpegMediaMetadataRetriever.METADATA_KEY_DURATION);

// FFmpegMediaMetadataRetriever doesn't have the ability to get Width and Height of video, needed to scale down to 1024.
MediaMetadataRetriever retriever1 = new MediaMetadataRetriever();
retriever1.setDataSource(getPath(EditVideo.this, mMediaUri));
int width = Integer.parseInt(retriever1.extractMetadata(MediaMetadataRetriever.METADATA_KEY_VIDEO_WIDTH));
int height = Integer.parseInt(retriever1.extractMetadata(MediaMetadataRetriever.METADATA_KEY_VIDEO_HEIGHT));
retriever1.release();

int videoDuration = Integer.parseInt(time);

int newWidth = 1024;
int newHeight = Math.round(height * (1024f / width));

Bitmap bitmap;
for(int i=0;i<videoDuration;i+=mFrameEvery){

long startTime = System.currentTimeMillis();
bitmap = retriever.getFrameAtTime(i*1000, FFmpegMediaMetadataRetriever.OPTION_CLOSEST);
long endTime = System.currentTimeMillis();

Log.d(TAG,"Took: " + ((endTime - startTime) / 1000f));

final Bitmap scaledBitmap = Bitmap.createScaledBitmap(bitmap, newWidth, newHeight, false);

try {
File frameFile = getOutputMediaFile("IMAGEFILE",rev.size());
FileOutputStream fos = new FileOutputStream(frameFile);
scaledBitmap.compress(Bitmap.CompressFormat.PNG, 80, fos);
fos.close();

rev.add(frameFile.getAbsolutePath());

runOnUiThread(new Runnable() {
@Override
public void run() {
imageView.setImageBitmap(scaledBitmap);
totalFrames.setText("Total Frames: " + rev.size());
}
});
} catch (FileNotFoundException e) {
Log.d(TAG, "File not found: " + e.getMessage());
} catch (IOException e) {
Log.d(TAG, "Error accessing file: " + e.getMessage());
}
}
runOnUiThread(new Runnable() {
@Override
public void run() {
progressBar.setVisibility(View.INVISIBLE);
seekBar.setEnabled(true);
}
});
}
}).start();

日志:
D/EditVideo: Took: 1.448
D/EditVideo: Took: 1.147
D/EditVideo: Took: 1.162
D/EditVideo: Took: 1.322
D/EditVideo: Took: 1.301
D/EditVideo: Took: 1.453
D/EditVideo: Took: 1.108
D/EditVideo: Took: 1.165
D/EditVideo: Took: 1.292
D/EditVideo: Took: 1.358
D/EditVideo: Took: 1.369
D/EditVideo: Took: 1.06
D/EditVideo: Took: 1.13
D/EditVideo: Took: 1.183
D/EditVideo: Took: 1.177
D/EditVideo: Took: 1.231
D/EditVideo: Took: 0.924
D/EditVideo: Took: 1.007
D/EditVideo: Took: 1.092
D/EditVideo: Took: 1.104
D/EditVideo: Took: 1.211
D/EditVideo: Took: 0.923
D/EditVideo: Took: 0.994
D/EditVideo: Took: 1.119
D/EditVideo: Took: 1.138
D/EditVideo: Took: 1.193

最佳答案

我使用 MediaMetadataRetriver,平均处理时间约为 0.7 秒。我还找到了一些方法来减少获取框架的时间。

关于java - Android FFmpegMediaMetadataRetriever.getFrameAtTime() 很慢,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33625764/

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com