sql - 数据透视表行到列

Question

我正在使用 SQLServer2008 Express
我有一个表和一个脚本，用于将行转换为具有预期结果的列

PARENT_ID   name01  name02  name03  name04  
1           ABC     DEF     ABC2    DEF2
2            DEF3    null    null    null

但是，我得到的结果是

PARENT_ID    name01    name02    name03    name04  
1            ABC       DEF       ABC2      DEF2
2            null      null      null      null  

我知道代码有问题，只是我想不通。希望有人能帮忙。

CREATE TABLE #temp (
    parent_id            bigint NOT NULL
    ,dependent_id        bigint not null
    ,date_of_birth       date not null
    ,last_name           varchar(100)
    ,first_name           varchar(100)
    ,effective_start_date date
    ,effective_end_Date   date
)  
insert into #temp values (1,1,'1990-10-01','ABC',null,'1989-01-01','9999-12-31')  
insert into #temp values (1,2,'1991-06-02','DEF',null,'1989-01-01','9999-12-31')  
insert into #temp values (1,3,'1992-06-02','ABC2',null,'1989-01-01','9999-12-31')  
insert into #temp values (1,4,'1993-06-02','DEF2',null,'1989-01-01','9999-12-31')  
insert into #temp values (2,5,'2000-06-02','DEF3',null,'1989-01-01','9999-12-31')  

SELECT PARENT_ID  
    ,[1] as name01  
    ,[2] as name02  
    ,[3] as name03  
    ,[4] as name04  
FROM ( SELECT top(100)  percent
    PARENT_ID  
   , dependent_id  
   , (isnull(first_name,'')+last_name) as fullname  
FROM #temp  
where GETDATE() between effective_start_date and effective_end_Date  
order by date_of_birth  
   ) AS piv  
PIVOT ( max(fullname)  
  FOR dependent_id IN ([1], [2], [3], [4])  
  ) AS chld  

谢谢埃尔默

Answer 1

我认为是数据而不是代码有问题。您要插入 5 作为 dependent_id 但希望它出现在 1 列中？

你也许可以使用 dependent_id % 4 但我不确定这里的意图是什么？

编辑 根据您的评论，我认为您需要这个？

SELECT PARENT_ID  
    ,[1] as name01  
    ,[2] as name02  
    ,[3] as name03  
    ,[4] as name04  
FROM 
(
  SELECT  
    PARENT_ID,
    ROW_NUMBER() OVER (PARTITION BY PARENT_ID ORDER BY date_of_birth) AS RN
   , (isnull(first_name,'')+last_name) as fullname  
FROM #temp  
where GETDATE() between effective_start_date and effective_end_Date  
) AS piv  
PIVOT ( max(fullname)  
  FOR RN IN ([1], [2], [3], [4])  
  ) AS chld