php - MethodNotAllowedHttpException，重定向到 404

Question

这是一组 Controller 的列表:

Route::group([
        'prefix'     => 'some-prefix',
    ], function () {
        Route::get('/', 'MyController@index')->name('some-prefix');
        Route::post('/get', 'MyController@getData')->name('some-prefix.get');
        Route::get('/getall/{type}', 'MyController@getAllData')->name('some-prefix.getall');
        Route::get('/create', 'MyController@create')->name('some-prefix.create');
        Route::post('/', 'MyController@store')->name('some-prefix.store');
        Route::get('/edit', 'MyController@edit')->name('some-prefix.edit');
        Route::get('/{id}/edit/', 'MyController@edit')->name('some-prefix.edit');
        Route::put('/{id}', 'MyController@update')->name('some-prefix.update');
        Route::get('/cambiarestado/{id}', 'MyController@cambiarestado')->name('some-prefix.cambiarestado');
    });

我想在输入 URL 时重定向到 404 错误:

http://myapp.com/some-prefix/ANYTHING-that-doesnt-match

这是我收到下一个错误的时间:

(1/1) MethodNotAllowedHttpException
in RouteCollection.php (line 251)
at RouteCollection->methodNotAllowed(array('PUT'))
in RouteCollection.php (line 238)
at RouteCollection->getRouteForMethods(object(Request), array('PUT'))
in RouteCollection.php (line 176)

我放了一个 failOrFind在我的 store 里面和 edit Controller 中的方法，因此我可以将其还原为 404 路由，例如:

http://myapp.com/some-prefix/9999/edit

其中值 9999不存在，但我该怎么做我问的？

Answer 1

转至 App\Exception打开handler.php在 render()方法添加:

 public function render($request, Exception $exception)
 {
    if($exception instanceof \Symfony\Component\HttpKernel\Exception\MethodNotAllowedHttpException){
      return abort('404');
    }

    return parent::render($request, $exception);
 }