arrays - Powershell 2 : Array size differs between return value and caller

Question

几个小时以来，我一直在努力解决这个问题，而谷歌也无济于事。

我有一个在我的代码中调用的函数。调用如下所示:

$newData = @(CreateMailContactIfNeeded $entry)

被调用的函数应始终返回一个 2 元素数组。我确认这个
在被调用函数的 return 语句之前:

# ... (inside CreateMailContactIfNeeded) ...
$tmpArr = @("$contactString" , "external")
Write-Host "length is" $tmpArr.length
Write-Host "Contact string is ->"$contactString"<-"
return $tmpArr

长度始终为 2，并且联系人字符串始终为非空。示例输出:

length is 2
Contact string is -> GMSContact-33<-

(我无法去除字符串中的前导空格，所以我认为这是某种
内部powershell字符串格式或其他东西)

但是，当我回到调用函数时，有时但并非总是如此
我从返回值构建的数组长度为三:

if ($newData.length -eq 3) {
  Write-Host "Weird - array length is 3..."
}

Write-Host "Array length now is "$newData.length
foreach ($tmpVar in $newData) {
  Write-Host "Array entry is "$tmpVar
}

3-entry 数组的第一个元素是一个有效的字符串，但它是来自
前期处理:

Weird - array length is 3...
Array length now is  3
Array entry is  Test User       <-- INVALID
Array entry is  GMSContact-33   <-- This should be first element
Array entry is  external        <-- This should be second element

有人可以向我解释可能发生了什么以及如何解决吗？我是否错误地进行了数组分配？鉴于上面的代码，“测试用户”怎么可能被插入到数组中？

编辑:下面 CreateMailContactIfNeeded 的全部内容...

function CreateMailContactIfNeeded {
  param($CSVEntry)

  $email = $CSVEntry.EMAIL_ADDR

  Write-Host    "--> Searching for $email"
  Write-Host -n "----> In AD? "
   # Return if this person already exists as a user in AD
  if (IsInOurADDomain $CSVentry) {
    Write-Host -f green "YES."
    Write-Host "Returning "$email "= inhouse"
    return @("$email" , "inhouse")
  } else {
    Write-Host -n -f gray "NO. "
  }

  $contactString = "GMSContact-" + $CSVEntry.MEMBER_ID
  Write-Host "Contact string is now " $contactString

  # Check if mail contact already exists. If not, create it.
  Write-Host -n "In Contacts? "
  $object = Get-MailContact $email 2> $null

  if ($object -eq $null) {
    $displayName = $CSVentry.FIRST_NAME + " " + $CSVentry.LAST_NAME

    Write-Host -n -f gray "NO. "
    Write-Host -n "Creating contact... "

    $error.clear()
    New-MailContact -Name $contactString                    `
                    -DisplayName $displayName               `
                    -ExternalEmailAddress $email            `
                    -OrganizationalUnit $global:OU_CONTACT_STRING  
    if ($error[0] -ne $null) {
      Write-Host -f red "ERROR"
      Write-Error $error[0]
      return @("error","error")
    }
    # Derek says to do this to make it appear in alternate address book
    Set-MailContact -identity $contactString -customattribute1 "AB2"
    Write-Host -f green "SUCCESSFUL"
  } else {
    Write-Host -f green "YES"
  }
  Write-Host "Returning" $contactString "= external"
  $tmpArr = @("$contactString" , "external")
  Write-Host "length is" $tmpArr.length
  Write-Host "Contact string is ->"$contactString"<-"
  Write-Host "Contact string length is "$contactString.length
   foreach ($tmp in $tmpArr) {
     Write-Host "In function element is "$tmp
   }
   return $tmpArr
#  return @("$contactString" , "external")
}

Answer 1

在 Poweshell 中，任何未被“捕获”的东西都会被有效地“返回”。

让我们举个例子:

function test(){

    "starting processing"

    #do some processing

    write-host "starting different process"
    $output = @("first",second")
    return $output
}

当你做类似 $myoutput =test 的事情时，你会看到 $myoutput 实际上有三个元素 - first,second正如预期的那样，还有 starting processing .因为 starting processing未被捕获并“返回”到管道中。

只要在脚本中生成无效的“TEST USER”输出，请 try catch 输出或通过管道将其传送到 Out-Null或将其分配给 $null
找出额外元素从哪里“返回”的简单方法。

更改脚本，以便您不会在变量中捕获函数的输出。所以留下它为 CreateMailContactIfNeeded $entry
在运行脚本之前，运行 Set-PsDebug -trace 1 .现在，运行脚本 - 您应该能够看到 TEST USER正在被退回。按照上面的建议捕获它。