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java - 使用 Xuggler 将音频(aac)和视频(mp4 容器中的 h.264)合并到 mp4 容器中

转载 作者:行者123 更新时间:2023-12-04 23:28:10 24 4
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这是我正在使用的代码

    String filenamevideo = videoFilePath;(video.mp4)

String filenameaudio = audioAACFilePath; (audio.aac)



IMediaWriter mWriter = ToolFactory.makeWriter(videoWithAudioFilePath); // output
// file

IContainer containerVideo = IContainer.make();
IContainer containerAudio = IContainer.make();

if (containerVideo.open(filenamevideo, IContainer.Type.READ, null) < 0)
throw new IllegalArgumentException("Cant find " + filenamevideo);

if (containerAudio.open(filenameaudio, IContainer.Type.READ, null) < 0)
throw new IllegalArgumentException("Cant find " + filenameaudio);

int numStreamVideo = containerVideo.getNumStreams();
int numStreamAudio = containerAudio.getNumStreams();

int videostreamt = -1; // this is the video stream id
int audiostreamt = -1;

IStreamCoder videocoder = null;

for (int i = 0; i < numStreamVideo; i++) {
IStream stream = containerVideo.getStream(i);
IStreamCoder code = stream.getStreamCoder();

if (code.getCodecType() == ICodec.Type.CODEC_TYPE_VIDEO) {
videostreamt = i;
videocoder = code;
break;
}

}

for (int i = 0; i < numStreamAudio; i++) {
IStream stream = containerAudio.getStream(i);
IStreamCoder code = stream.getStreamCoder();

if (code.getCodecType() == ICodec.Type.CODEC_TYPE_AUDIO) {
audiostreamt = i;
break;
}

}

if (videostreamt == -1)
throw new RuntimeException("No video steam found");
if (audiostreamt == -1)
throw new RuntimeException("No audio steam found");

if (videocoder.open() < 0)
throw new RuntimeException("Cant open video coder");
IPacket packetvideo = IPacket.make();

IStreamCoder audioCoder = containerAudio.getStream(audiostreamt).getStreamCoder();

if (audioCoder.open() < 0)
throw new RuntimeException("Cant open audio coder");

mWriter.addAudioStream(0, 0, ICodec.ID.CODEC_ID_AAC, audioCoder.getChannels(),audioCoder.getSampleRate());

mWriter.addVideoStream(1, 0, ICodec.ID.CODEC_ID_H264, videocoder.getWidth(), videocoder.getHeight());


IPacket packetaudio = IPacket.make();

while (containerVideo.readNextPacket(packetvideo) >= 0 || containerAudio.readNextPacket(packetaudio) >= 0) {

if (packetvideo.getStreamIndex() == videostreamt) {

// video packet
IVideoPicture picture = IVideoPicture.make(videocoder.getPixelType(), videocoder.getWidth(),
videocoder.getHeight());
int offset = 0;
while (offset < packetvideo.getSize()) {
int bytesDecoded = videocoder.decodeVideo(picture, packetvideo, offset);
if (bytesDecoded < 0)
throw new RuntimeException("bytesDecoded not working");
offset += bytesDecoded;
if (picture.isComplete()) {
// System.out.println(picture.getPixelType());
mWriter.encodeVideo(1, picture);
}
}
}

if (packetaudio.getStreamIndex() == audiostreamt) {
// audio packet
IAudioSamples samples = IAudioSamples.make(512, audioCoder.getChannels(), IAudioSamples.Format.FMT_S32);
int offset = 0;
while (offset < packetaudio.getSize()) {
int bytesDecodedaudio = audioCoder.decodeAudio(samples, packetaudio, offset);
if (bytesDecodedaudio < 0)
throw new RuntimeException("could not detect audio");
offset += bytesDecodedaudio;
if (samples.isComplete()) {
mWriter.encodeAudio(0, samples);
}
}

}
}

输出文件 (mp4) 正在生成,但无法使用 (vlc) 和 JavaFX 场景媒体播放。

请帮助我输入上述代码的输入,我以正确的方式使用它(或)帮助我解决将音频(aac)和视频(h264)合并到 mp4 容器的可能解决方案。

预先感谢。

最佳答案

所有的流都必须结束。你所有的仍然是开放的。

关于java - 使用 Xuggler 将音频(aac)和视频(mp4 容器中的 h.264)合并到 mp4 容器中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33923058/

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