visual-studio - 通过 MSBuild 构建不同平台的 Visual Studio 项目

Question

我有 3 个带有配置的项目:

项目 A:调试|AnyCPU，发布|AnyCPU

项目 B:调试|AnyCPU，发布|AnyCPU

项目 C:调试|x86、调试|x64、发布|x86、发布|x64

项目 C 的依赖项中有 B，而 B 的依赖项中有 A。 (A <- B <- C)

我使用 *.bat 文件从命令行构建它:

msbuild A.csproj /target:Build /property:Configuration=Debug;Platform=AnyCPU /verbosity:minimal
msbuild A.csproj /target:Build /property:Configuration=Release;Platform=AnyCPU /verbosity:minimal<br/>
msbuild B.csproj /target:Build /property:Configuration=Debug;Platform=AnyCPU /verbosity:minimal
msbuild B.csproj /target:Build /property:Configuration=Release;Platform=AnyCPU /verbosity:minimal
msbuild C.csproj /target:Build /property:Configuration=Debug;Platform=x86 /verbosity:minimal
msbuild C.csproj /target:Build /property:Configuration=Release;Platform=x86 /verbosity:minimal
msbuild C.csproj /target:Build /property:Configuration=Debug;Platform=x64 /verbosity:minimal
msbuild C.csproj /target:Build /property:Configuration=Release;Platform=x64 /verbosity:minimal

并收到错误:

C:\Windows\Microsoft.NET\Framework64\v4.0.30319\Microsoft.Common.targets(609,5): error : The OutputPath property is not set for project 'A.csproj'. Please check to make sure that you have specified a valid combination of Configuration and Platform for this project. Configuration='Debug' Platform='x86'. You may be seeing this message because you are trying to build a project without a solution file, and have specified a non-default Configuration or Platform that doesn't exist for this project. [A.csproj] C:\Windows\Microsoft.NET\Framework64\v4.0.30319\Microsoft.Common.targets(609,5): error : The OutputPath property is not set for project 'B.csproj'. Please check to make sure that you have specified a valid combination of Configuration and Platform for this project. Configuration='Debug' Platform='x86'. You may be seeing this message because you are trying to build a project without a solution file, and have specified a non-default Configuration or Platform that doesn't exist for this project. [B.csproj]

Answer 1

我找到了解决我的问题的方法。
使用 *.csproj 文件中的选择元素通过 Visual Studio 或 MSBuild 检测构建，并使用 Reference(而不是 ProjectReference)进行 MSBuild。

<Choose>
  <When Condition="'$(BuildingInsideVisualStudio)' == 'true'">
    <ItemGroup>
      <ProjectReference Include="A.csproj">
        <Project>{AAAAAAAA-AAAA-AAAA-AAAA-AAAAAAAAAAAA}</Project>
        <Name>A</Name>
        <Private>True</Private>
      </ProjectReference>
      <ProjectReference Include="B.csproj">
        <Project>{BBBBBBBB-BBBB-BBBB-BBBB-BBBBBBBBBBBB}</Project>
        <Name>B</Name>
        <Private>True</Private>
      </ProjectReference>
    </ItemGroup>
  </When>
  <Otherwise>
    <ItemGroup>
      <Reference Include="A, Version=1.0.0.0, Culture=neutral, PublicKeyToken=xxxxxxxxxxxxxxxx, processorArchitecture=MSIL">
        <HintPath>A.dll</HintPath>
        <Private>True</Private>
      </Reference>
      <Reference Include="B, Version=1.0.0.0, Culture=neutral, PublicKeyToken=xxxxxxxxxxxxxxxx, processorArchitecture=MSIL">
        <HintPath>B.dll</HintPath>
        <Private>True</Private>
      </Reference>
    </ItemGroup>
  </Otherwise>
</Choose>