python - 如何在机器人播放后删除 mp3 文件

Question

我正在尝试创建一个音乐机器人，现在我希望机器人在完成播放后删除当前正在播放的歌曲。这是我的代码:

import asyncio

import os
import discord
from discord.embeds import Embed
from discord.file import File
from discord.player import AudioPlayer
from youtube_dl.utils import smuggle_url, update_url_query
from youtube_search import YoutubeSearch
import discord
from discord.ext.commands import bot
import youtube_dl
from discord.ext import commands
from youtube_dl import YoutubeDL

youtube_dl.utils.bug_reports_message = lambda: ''

ytdl_format_options = {
    'format': 'bestaudio/best',
    'outtmpl': '/music_files/%(id)s.mp3',
    'restrictfilenames': True,
    'noplaylist': True,
    'nocheckcertificate': True,
    'ignoreerrors': False,
    'logtostderr': False,
    'quiet': True,
    'no_warnings': True,
    'default_search': 'auto',
    'source_address': '0.0.0.0' 
}

ffmpeg_options = {
    'options': '-vn'
}

ytdl = youtube_dl.YoutubeDL(ytdl_format_options)


class YTDLSource(discord.PCMVolumeTransformer):
    def __init__(self, source: discord.FFmpegPCMAudio, *, data: dict, volume=0.5):
        super().__init__(source, volume)

        self.data = data

        self.title = data.get('title')
        self.thumbnail = data.get('thumbnail')
        self.url = data.get('webpage_url')
        self.uploader = data.get('uploader')
        self.uploader_url = data.get('uploader_url')

    @classmethod
    async def from_url(cls, url, *, loop=None, stream=False):
        loop = loop or asyncio.get_event_loop()
        data = await loop.run_in_executor(None, lambda: ytdl.extract_info(url, download=not stream))

        if 'entries' in data:
            # take first item from a playlist
            data = data['entries'][0]

        filename = data['url'] if stream else ytdl.prepare_filename(data)
        return cls(discord.FFmpegPCMAudio(filename, **ffmpeg_options), data=data)

class Music(commands.Cog):
    def __init__(self, bot):
        self.bot = bot


    @commands.command()
    async def play(self, ctx, *, url):
        global player
        """Plays from a url (almost anything youtube_dl supports)"""
        async with ctx.typing():
            player = await YTDLSource.from_url(url, loop=self.bot.loop)
            ctx.voice_client.play(player, after=lambda e: print('Player error: %s' % e) if e else None)

            await ctx.send("Started playing!")
    @play.before_invoke
    async def ensure_voice(self, ctx):
        if ctx.voice_client is None:
            if ctx.author.voice:
                await ctx.author.voice.channel.connect()
            else:
                await ctx.send("You are not connected to a voice channel.")
                raise commands.CommandError("Author not connected to a voice channel.")
        elif ctx.voice_client.is_playing():
            ctx.voice_client.stop()

def setup(client):
    client.add_cog(Music(client))

它将文件保存到名为“music_files”的文件夹中，格式为 videoid.mp3
我注意到它在 logging.basicConfig(level=logging.INFO) 时在 cmd 中记录了一些东西被添加到imports下的main.py文件中，有没有办法使用它？
注意:代码是 basic_voice.py的修改版本通过拉普茨。
编辑:我找到了一种方法:

            folder = './music_files'
            for song in os.listdir(folder):
                file_path = os.path.join(folder, song)
                try:
                    if os.path.isfile(file_path) or os.path.islink(file_path):
                        os.unlink(file_path)
                    elif os.path.isdir(file_path):
                        shutil.rmtree(file_path)
                except Exception as e:
                    print('Failed to delete %s. Reason %s' % (file_path, e))

Answer 1

您可以使用 os.remove(f'PATH/{videoid}.mp3') 删除文件