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oracle - ORA-01007 : variable not in select list

转载 作者:行者123 更新时间:2023-12-04 23:19:06 26 4
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我试图通过返回选择查询将多个值插入到特定表中,但我无法将其插入表中。如果我在某个地方做错了,请让我知道。在此先感谢您。

create or replace PROCEDURE DE_DUP_PROC1 (Dy_File_Name    IN     VARCHAR2,    
SUPPLIER_CD IN VARCHAR2,
EXT_PHARMA_ID IN VARCHAR2,
FLAG_VALUE IN VARCHAR2,
ERR_COUNT IN VARCHAR2,
OUTPUT_STATUS OUT NUMBER)

AS
c2 SYS_REFCURSOR;
De_Dub_rec1 VARCHAR2 (2000);
v_sql VARCHAR2 (2000);
v_sql1 VARCHAR2 (2000);
ORGNIZATION_ID NUMBER(20);
PHARMACY_ID NUMBER(38);
v_dup_count VARCHAR2 (2000);
SRC_ID NUMBER(38);
DE_DUP_COUNT NUMBER(38);
DE_REC_COUNT1 NUMBER(10) := 3;

TYPE rec_typ IS RECORD
(
OLD_TRANS_GUID VARCHAR2 (255),
R_DSPNSD_DT DATE,
DETL_CLMNS_HASH1 VARCHAR2(255),
KEY_CLMNS_HASH1 VARCHAR2(255),
SUPPLIER_PHARMACY_CD1 VARCHAR2(200)
);
De_Dub_rec rec_typ;

BEGIN

IF DE_REC_COUNT1 > 0
THEN

OUTPUT_STATUS := 0;
dbms_output.put_line(OUTPUT_STATUS);

ELSE

SRC_ID := SRC_FILE_ID_SEQ.nextval
OPEN c2 FOR
( ' SELECT S.TRANS_GUID AS OLD_TRANS_GUID,S.DETL_CLMNS_HASH AS DETL_CLMNS_HASH1 ,S.KEY_CLMNS_HASH AS KEY_CLMNS_HASH1,S.RX_DSPNSD_DT AS R_DSPNSD_DT,
S.SUPPLIER_PHARMACY_CD AS SUPPLIER_PHARMACY_CD1 FROM (SELECT stg.*, row_number() over (partition BY key_clmns_hash ORDER BY 1) AS RN FROM
' || Dy_File_Name || ' stg ) s JOIN ps_pharmacy p ON s.extrnl_pharmacy_id = p.extrnl_pharmacy_id LEFT JOIN ps_rx_hist H
ON h.key_clmns_hash = s.key_clmnS_hash
AND h.rx_dspnsd_dt = s.rx_dspnsd_dt
AND s.supplier_pharmacy_cd = h.SUPPLIER_PHARMACY_CD
WHERE S.RN > 1
OR s.detl_clmns_hash = h.detl_clmns_hash ' );

LOOP

FETCH c2 INTO De_Dub_rec;

EXIT WHEN c2%NOTFOUND;

insert into PS_RX_DUPES(TRANS_GUID,DETL_CLMNS_HASH,KEY_CLMNS_HASH,RX_DSPNSD_DT,SUPPLIER_PHARMACY_CD,SRC_FILE_ID)
values(De_Dub_rec.OLD_TRANS_GUID,De_Dub_rec.DETL_CLMNS_HASH1,De_Dub_rec.KEY_CLMNS_HASH1,De_Dub_rec.R_DSPNSD_DT,De_Dub_rec.SUPPLIER_PHARMACY_CD1,SRC_ID);

commit;
END LOOP;

OUTPUT_STATUS := 1;
dbms_output.put_line(OUTPUT_STATUS);

END IF;

END DE_DUP_PROC1;

每当我执行上面的存储过程时,我下面的错误
declare
OUTPUT_STATUS number(2);
begin
DE_DUP_PROC1('T_MCL_10622_20150317_01526556','MCL','10622','BD','3',OUTPUT_STATUS);
end;
Error at line 1
- ORA-01007: variable not in select list
ORA-06512: at "PS_ADMIN.DE_DUP_PROC1", line 53
ORA-06512: at line 6

最佳答案

当查询的列与目标变量不匹配时,Oracle会发送ORA-01007
第53行是此行FETCH c2 INTO De_Dub_rec;,因此线索是光标的投影与记录类型不匹配。
您的自由文本SELECT语句布局困惑,这使调试变得很困难。让我们整理一下投影:

SELECT S.TRANS_GUID             AS OLD_TRANS_GUID
, S.DETL_CLMNS_HASH AS DETL_CLMNS_HASH1
, S.KEY_CLMNS_HASH AS KEY_CLMNS_HASH1
, S.RX_DSPNSD_DT AS R_DSPNSD_DT
, S.SUPPLIER_PHARMACY_CD AS SUPPLIER_PHARMACY_CD1
FROM ...
现在可以很容易地看到列顺序与类型的属性顺序不同:
   TYPE rec_typ IS RECORD    
(
OLD_TRANS_GUID VARCHAR2 (255),
R_DSPNSD_DT DATE,
DETL_CLMNS_HASH1 VARCHAR2(255),
KEY_CLMNS_HASH1 VARCHAR2(255),
SUPPLIER_PHARMACY_CD1 VARCHAR2(200)
);
因此,您的代码正在尝试将字符串放入日期变量中(反之亦然,但至少Oracle可以强制转换)。
所有这些都证明,清晰的布局并不是愚蠢的强制症。编写代码的纪律可以通过突出显示明显的错误来帮助我们更快地编写更好的代码。

关于oracle - ORA-01007 : variable not in select list,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32485978/

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